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KonstantinChe [14]

3 years ago

9

Need help with this one

2 answers:

Simora [160]3 years ago

6 0

Answer:

try c

Step-by-step explanation:

Katena32 [7]3 years ago

6 0

The answer will be C

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Amelia used 1/7 of an ounce of butter to make 1/4 of a pound of Jello. How many ounces of butter are needed to make 1 pound of J

son4ous [18]

Answer:

4/7

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A package of tickets for 4 home games cost $180 . What proportion can you write to find what a 12 -game package cost if all indi

Amiraneli [1.4K]

You would write it like 4/180.
Then the other one would be
12/x.
To find the individual price you need to divide 180 by 4. You then get 45.
So now to find how many 12 tickets would be, multiply 12 by 45.
The answer would then be $540. Pricey!

Hope this helps!

6 0

3 years ago

Is 104 and 12 hundreths greater than 104 and 2 hundreths

Scilla [17]

Yes, 104.12 is greater than 104.02.

4 0

3 years ago

14 is 56% of what number

Eddi Din [679]

X= is the number looked for.
56% of x=14
We suggest this equation:
(56/100)x=14
x=(14*100)/56=25

Solution: 25

6 0

3 years ago

Find formula of s in terms of a, b, cos(x)

Alecsey [184]

Answer:

$\displaystyle s = \frac{2ab\cos x}{a+b}$

Step-by-step explanation:

We want to find a formula for <em>s</em> in terms of <em>a, b, </em>and cos(x).

Let the point where <em>s</em> intersects AB be D.

Notice that <em>s</em> bisects ∠C. Then by the Angle Bisector Theorem:

$\displaystyle \frac{a}{BD} = \frac{b}{AD}$

We can find BD using the Law of Cosines:

$\displaystyle BD^2 = a^2 + s^2 - 2as \cos x$

Likewise:

$\displaystyle AD^2 = b^2+ s^2 - 2bs \cos x$

From the first equation, cross-multiply:

$bBD = a AD$

And square both sides:

$b^2 BD^2 =a^2 AD^2$

Substitute:

$\displaystyle b^2 \left(a^2 + s^2 - 2as \cos x\right) = a^2 \left(b^2 + s^2 - 2bs \cos x\right)$

Distribute:

$a^2b^2 + b^2s^2 - 2ab^2 s\cos x = a^2b^2 + a^2s^2 - 2a^2 bs\cos x$

Simplify:

$b^2 s^2 - 2ab^2 s \cos x = a^2 s^2 - 2a^2 b s \cos x$

Divide both sides by <em>s </em>(<em>s</em> ≠ 0):

$b^2 s -2ab^2 \cos x = a^2 s - 2a^2 b \cos x$

Isolate <em>s: </em>

$b^2 s - a^2s = -2a^2 b \cos x + 2ab^2 \cos x$

Factor:

$\displaystyle s (b^2 - a^2) = 2ab^2 \cos x - 2a^2 b \cos x$

Therefore:

$\displaystyle s = \frac{2ab^2 \cos x - 2a^2 b \cos x}{b^2- a^2}$

Factor:

$\displaystyle s = \frac{2ab\cos x(b - a)}{(b-a)(b+a)}$

Simplify. Therefore:

$\displaystyle s = \frac{2ab\cos x}{a+b}$

5 0

3 years ago