Answer:
Given A triangle ABC in which
∠C =90°,∠A=20° and CD ⊥ AB.
In Δ ABC
⇒∠A + ∠B +∠C=180° [ Angle sum property of triangle]
⇒20° + ∠B + 90°=180°
⇒∠B+110° =180°
∠B =180° -110°
∠B = 70°
In Δ B DC
∠BDC =90°,∠B =70°,∠BC D=?
∠BDC +,∠B+∠BC D=180°[ angle sum property of triangle]
90° + 70°+∠BC D =180°
∠BC D=180°- 160°
∠BC D = 20°
In Δ AC D
∠A=20°, ∠ADC=90°,∠AC D=?
∠A + ∠ADC +∠AC D=180° [angle sum property of triangle]
20°+90°+∠AC D=180°
110° +∠AC D=180°
∠AC D=180°-110°
∠AC D=70°
So solution are, ∠AC D=70°,∠ BC D=20°,∠DB C=70°
This is a function when u have f(n) u plug in the number for example 1 because the number -13 is the first number in the sequence
Answer:
If one −5s−7(8s−1): -61s+7
If two −5s−7(8s−1): -112s+14
Step-by-step explanation:
-5s-7(8s-1)
Multiply -7 onto 8s and -1:
-5s-56s+7
add -5s and -56s:
-61s+7
−5s−7(8s−1)−5s−7(8s−1)
Multiply both -7 to 8s and -1
-5s-56s+7-5s-56s+7
add:
-112s+14
The correct answer is D
The equation of a circle is (x-h)^2 + (y-k)^2 = r^2
to find (h,k), you find the middle of the circle, in this scenario you do so by finding the middle of the diameter, a line that goes through the center of the circle.
To find the X value of the midpoint, add both x values together and divide by 2 and repeat for y
-13 + -1 = -14
-14/2 =-7
10+ -6 = 4
4/2 = 2
therefore (h,k) = ( -7, 2 )
Next plug these values in the equation of a circle
(x-h)^2 + (y-k)^2 = r^2
becomes
(x- (-7)) ^2 + (y-(2)) ^2 = r^2
to find r, use the distance formula to find the length of the diameter, 20, and divide by 2
plug 10 in for r and you get 100
(x+7)^2 + (y-2)^2 = 100
sorry for the late response
#7:
<span>Subtract </span>y<span> from both sides:
</span>-4x=6-y
Divide both sides by -4:
Answer:
x= -6-y/4
#7 part 2:
Add <span>y</span><span> to both sides:
</span>-5x=21+y
Divide both sides by -5:
Answer: x=-21+y/5
hope i helped!
