The area is 36 units squared.
You have three ways you can solve this question.
Method 1:
Split the rhombus into two equal triangles.
You will get triangle ACD and triangle ACB.
Count the base length and height length of each triangle using the diagram.
You will get base = 6 units and height = 6 units. Plug this into the area of a triangle and then multiply it by 2.
A = bh/2 * 2
A = 6(6) / 2 * 2
A = 36 / 2 * 2
A = 18 * 2
A = 36
Method 2:
Calculate the length of DP.
The length of line segment DP is √28.8
Calculate the length of DC.
The length of line segment DC is 3√5
Put into equation A = bh.
A = bh
A = 3√5(√28.8)
A = 36
Method 3:
Calculate the length of each diagonal and put into formula A = 1/2(d1 * d2)
Diagonal DB = 12 units
Diagonal AC = 6 units
A = 1/2(d1 * d2)
A = 1/2(12 * 6)
A = 1/2(72)
A = 36
I love procrastinating my history essay for this :D
(y+2)=1/4(x-4) is the answer because you use the formula (y-y1)=slope(x-x1)
9514 1404 393
Answer:
x = 4
Step-by-step explanation:
The parallel lines divide the sides proportionally, so ratios of corresponding sides are the same.
(x +5)/15 = (5x +1)/35
Multiplying by 105, we have ...
7(x +5) = 3(5x +1)
7x +35 = 15x +3 . . . . . eliminate parentheses
32 = 8x . . . . . . . . . subtract 7x+3 from both sides
4 = x . . . . . . . . divide by 8
Answer:
The angle between the two sides of the right triangle is aproximately 31.003º.
Step-by-step explanation:
From image attached on question we infer that we need to find the angle between sides of lengths 6 (adjacent leg) and 7 (hypotenuse) in the right triangle. The angle can be found by means of this trigonometric ratio:
The angle between the two sides of the right triangle is aproximately 31.003º.
Answer:
Step-by-step explanation:
1000m=1k
3,500m=3.5k
500m=.5k
75m=0.075k
1m=0.001
