Answer:
25 y 3−15 y 2−10 y ... 25y3 - 15y2 - 10y = 5y • (5y2 - 3y - 2) ... 5y • (y-1) Add up the last 2 terms, pulling out common factors : 2 • (y-1
7(n - p) + 5p
7n - 7p + 5p
7n - 2p
Answer:
(x - 1)( x - 2) (x + 2) = x³ -x² -4x + 4.
Explanation:
1) Given equation:
3 5x x + 2
- ------- + -------- = ---------------
x + 2 x - 1 x² - 3x + 2
2) So, the denominators are x + 2, x - 1, and x² - 3x + 2
3) The LCD is the product of the common and non common factors raised to the greatest power.
4) x + 2, and x - 1 are already prime factors
5) Factor x² - 3x + 2
x² - 3x + 2 = (x - 2)(x - 1)
6) Then, the factors are x + 2, x - 1, and x - 2, and the LCD is the product of them:
(x - 1)( x - 2) (x + 2)
7) If you expand the products (distributive property) you get:
x³ -x² -4x + 4.
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