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Kay [80]
4 years ago
7

How can you express (16 + 40) as a multiple of a sum of whole numbers with no common factor?

Mathematics
1 answer:
Dafna11 [192]4 years ago
5 0

The answer is B

4(4+10)

4*4=16

4*10=40 which will give you (16+40)

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An item is regularly priced at $70. Chang bought it on sale for 60% off the regular price. How much did Chang pay?
elena-14-01-66 [18.8K]

Answer: $42

Step-by-step explanation:

You need to find 60% of 70

10%= 7 (70/10)

60% = 42 (7x6)

so the answer is $42

3 0
3 years ago
Read 2 more answers
If the terminal side of angle 0 in standard position intersects the unit circle at p (3/5,4/5). Find cos0 and sin0
Rina8888 [55]

Answer:

\sin \theta = \frac{4}{5}, \cos \theta = \frac{3}{5}

Step-by-step explanation:

Let be P(x,y) = \left(\frac{3}{5}, \frac{4}{5}  \right) the end of the terminal side of angle \theta in standard position, that is, an angle measured with respect to +x semiaxis. By Trigonometry, we know that the sine and the cosine of the angle are, respectively:

\sin \theta = \frac{y}{\sqrt{x^{2} + y^{2}}} (1)

\cos \theta = \frac{x}{\sqrt{x^{2}+y^{2}}} (2)

If we know that x = \frac{3}{5} and y = \frac{4}{5}, then the sine and the cosine of the angle are:

\sin \theta = \frac{\frac{4}{5} }{\sqrt{\left(\frac{3}{5} \right)^{2}+\left(\frac{4}{5} \right)^{2}}}

\sin \theta = \frac{4}{5}

\cos \theta = \frac{\frac{3}{5} }{\sqrt{\left(\frac{3}{5} \right)^{2}+\left(\frac{4}{5} \right)^{2}}}

\cos \theta = \frac{3}{5}

3 0
3 years ago
Please Helpppppppppp!!!!!!!!!!!!!!!
viktelen [127]

Answer:

122/3435.35/67

Step-by-step explanation:

7 0
3 years ago
H(x)=-x^2+6x. So what is the value of h(2)
crimeas [40]

✩ Answer:

 ✧・゚: *✧・゚:*✧・゚: *✧・゚:*✧・゚: *✧・゚:*

  \bold{Hello!}\\\bold{Your~answer~is~below!}

✩ Step-by-step explanation:

 ✧・゚: *✧・゚:*✧・゚: *✧・゚:*✧・゚: *✧・゚:*

✺ Quadratic polynomials can be factored using the transformation ax^2+bx+c=a(x-x_{1})(x-x_{2} ), where x_{1} and x_{2} are the solutions of the quadratic equation ax^2+bx+c=0:

  • -x^2+6x=0

✺ All equations of the form ax^2+bx+c=0 can be solved using the quadratic formula:

  • -b=\frac{+}\\\sqrt{b^2-4ac}\\~~~~~~~~~~~~~2a

✺ The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction:

  • x=\frac{\sqrt{-6\frac{+}\\\sqrt{6^2}}}{2(-1)}

✺ Take the square root of 6^2:

  • x=\frac{\sqrt{-6\frac{+}\\{6}}}{2(-1)}

✺ Multiply 2 times -1:

  • x=\frac{\sqrt{-6\frac{+}\\{6}}}{-2}

✺ Now solve the equation x=\frac{\sqrt{-6\frac{+}\\{6}}}{-2} when ± is plus. Add -6 to 6:

  • x=\frac{0}{-2}

✺ Divide 0 by -2:

  • x=0

       -OR-

✺ Now solve the equation x=\frac{\sqrt{-6\frac{+}\\{6}}}{-2} when ± is minus. Subtract 6 from -6:

  • x=\frac{-12}{-2}

✺ Divide -12 by -2:

  • x=6

✺  Optional : Factor the original expression using ax^2+bx+c=a(x-x_{1})(x-x_{2} ). Substitute 0 for x_{1} and 6 for x_{2}:

  • -x^2+6x=-x(x-6)

✩ Answer:

✺ <u>Factored Form</u>: x(x-6)

✺ <u>Exact Form</u>: x=6

✺ <u>Graph Point Form</u>: x=(6,0)

Hope~this~helps~and,\\Best~of~luck!\\\\~~~~~-TotallyNotTrillex

             "ටᆼට"

8 0
4 years ago
Urgent! <br> Find the area created by the overlapping circles given the following information.
Stels [109]

Answer:

209.55in²

Step-by-step explanation:

Find area of sector CADE

Radius =22 in

Angle=90°

Formula to apply is ;

Ф/360 × π × r² where

Ф=angle of sector, π=3.142 and r =radius of circle

A=\frac{90}{360} *3.142*22*22=380.182in^2

Find area of triangle CAD where base length is 22 inches and height is 22 inches

Area of triangle formula is;

1/2×b×h where b is base and h is height

A=\frac{1}{2} *22*22=242in^2

Find area remaining

380.182-242=138.182in²

Find the area of sector CBDF

Radius=28in

Angle=60°

Formula to apply is ;

Ф/360 × π × r² where

Ф=angle of sector, π=3.142 and r =radius of circle

A=\frac{60}{360} *3.142*28*28=410.55in^2

Area of triangle BDC

The formula to apply is

1/2×a×a×sinФ where a=28 inches and Ф=60°

\frac{1}{2} *28*28*sin60=339.48in^2

Remaining area

410.55-339.48=71.075in²

Area created by overlapping circles

138.182+71.075=209.26in²

8 0
3 years ago
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