Question

Find the equation of a line given the point and slope below. Arrange your answer in the form y = mx + b, where b is the constant.
(1, 3)
m = 3

i need help with this question and others like it, an explanation would be great, im on a deadline and need to finish these as soon as possible ty

Answer 1

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cut-off point with the y axis

According to the data we have to:

$m = 3\\(x, y) :( 1,3)$

So, the equation is of the form:

$y = 3x + b$

We substitute the point and find b:

$3 = 3 (1) + b\\3 = 3 + b\\b = 3-3\\b = 0$

Finally, the equation is of the form:

$y = 3x$

Answer:

$y = 3x$

Answer 2

Answer:

y = 3x

Step-by-step explanation:

y = mx + b

(x,y) = (1,3)

m = 3

3 = 3(1) + b

3 = 3 + b

3 - 3 = b

0 = b

y = 3x