i feel like u are going to delete this but if this helped please don't delete it the answer is, Simon is correct because even though the input values are opposite in the reflected function, any real number can be an input.
(-4x2-5x-1)(4x2-6x-2)
Final result :
-2 • (13x + 1) • (2x2 - 3x - 1)
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "x2" was replaced by "x^2".
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(-13x - 1) • ((22x2 - 6x) - 2)
Step 2 :
Pulling out like terms :
3.1 Pull out like factors :
-13x - 1 = -1 • (13x + 1)
Step 3 :
Pulling out like terms :
4.1 Pull out like factors :
(4x2 - 6x - 2) = 2 • (2x2 - 3x - 1)
Trying to factor by splitting the middle term
4.2 Factoring 2x2 - 3x - 1
The first term is, 2x2 its coefficient is 2 .
The middle term is, -3x its coefficient is -3 .
The last term, "the constant", is -1
Step-1 : Multiply the coefficient of the first term by the constant 2 • -1 = -2
Step-2 : Find two factors of -2 whose sum equals the coefficient of the middle term, which is -3 .
-2 + 1 = -1
-1 + 2 = 1
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Step 4 :
Pulling out like terms :
5.1 Pull out like factors :
-26x - 2 = -2 • (13x + 1)
Final result :
-2 • (13x + 1) • (2x2 - 3x - 1)
Answer:
(7x^2 -1)(x - 2).
Step-by-step explanation:
7x^3 - 14x^2 - x + 2
We can factor this by grouping - that is factoring the first 2 terms and the last 2:
= 7x^2(x - 2) - 1(x - 2) <-- the x - 2 is common to both parts so we have:
(7x^2 -1)(x - 2).
Answer:
The equation of the line parallel to y=4/3x−4 that passes through (-4,6) is y=4/3x−10/3 .
The equation of the line perpendicular to y=43x−4 that passes through (-4,6) is y=−3/4x+10 .
Step-by-step explanation:
Parallel means equal slopes. Hence, the slope of the line parallel to y=4/3x+3 is 4/3 . We know our slope and we know a point. We can therefore use point-slope form to determine the equation of the new line.
y−y1=m(x−x1)
y−6=4/3(x−4)
y−6=4/3x−16/3
y=4/3x−7/3
The equation of the line parallel to y=4/3x−4 that passes through (-4,6) is y=4/3x−10/3 .
Question #2:
Perpendicular means negative reciprocal slopes. Hence, the slope perpendicular to y=4/3x+3 is y=−3/4 . We know our slope and we know a point. We can therefore use point-slope form to determine the equation of the new line.
y−y1=m(x−x1)
y−6=−3/4(x-4)
y−6=−3/4x+6
y=−3/4x+10
The equation of the line perpendicular to y=43x−4 that passes through (-4,6) is y=−3/4x+10 .
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