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Readme [11.4K]
3 years ago
13

Lim as x goes to 0: (2sinxcosx)/(2x^2+x)=

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
8 0
\displaystyle\lim_{x\to0}\frac{2\sin x\cos x}{2x^2+x}=2\left(\lim_{x\to0}\frac{\sin x }x\right)\left(\lim_{x\to0}\frac{\cos x}{x+1}\right)=2(1)\left(\frac1{0+1}\right)=2
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3 years ago
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omeli [17]

Answer:

  • x = - 6

Step-by-step explanation:

A hole is an input value that makes both numerator and denominator equal to zero.

<u>Let's factorize the numerator and denominator:</u>

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<u>We have same factor of x + 6:</u>

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