Lim as x goes to 0: (2sinxcosx)/(2x^2+x)=

1 answer:

8 0

$\displaystyle\lim_{x\to0}\frac{2\sin x\cos x}{2x^2+x}=2\left(\lim_{x\to0}\frac{\sin x }x\right)\left(\lim_{x\to0}\frac{\cos x}{x+1}\right)=2(1)\left(\frac1{0+1}\right)=2$

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