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Vikki [24]
3 years ago
7

PLEASE HELP FAST!!

Mathematics
1 answer:
victus00 [196]3 years ago
3 0

Answer:

triangle : 5, 2 , 13 represents a right triangle

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What is the y-intercept and slope of 0=1-2y+14x? :)
____ [38]

\bf 0=1-2y+14x\implies 2y=1+14x\implies 2y = 14x+1\implies y = \cfrac{14x+1}{2} \\\\\\ y = \cfrac{14x}{2}+\cfrac{1}{2}\implies y = \stackrel{\stackrel{m}{\downarrow }}{7} x+\cfrac{1}{2}\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

6 0
4 years ago
Rectangles ABCD and EFGH have the same shape. What is the length oh FG
tangare [24]
The length of FG would be BC. This is because FG and BC corresponds on the shape letter sequence. This would mean that EF would be AB, that GH would be CD, and that HE would be DA.
4 0
3 years ago
A hair salon uses 4 bottles of shampoo for every 3 bottles of conditioner.
Rama09 [41]

Answer:

I honestly think it is C.

Step-by-step explanation:

Since "4 bottles of shampoo for every 3 bottles of conditioner" is (4,3), I think the 16 is (16,12) on the graph. It might be worng, might be right. Just go for C.

7 0
3 years ago
This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex
olga nikolaevna [1]

f(x_1,\ldots,x_n)=x_1+\cdots+x_n=\displaystyle\sum_{i=1}^nx_i

{x_1}^2+\cdots+{x_n}^2=\displaystyle\sum_{i=1}^n{x_i}^2=4

The Lagrangian is

L(x_1,\ldots,x_n,\lambda)=\displaystyle\sum_{i=1}^nx_i+\lambda\left(\sum_{i=1}^n{x_i}^2-4\right)

with partial derivatives (all set equal to 0)

L_{x_i}=1+2\lambda x_i=0\implies x_i=-\dfrac1{2\lambda}

for 1\le i\le n, and

L_\lambda=\displaystyle\sum_{i=1}^n{x_i}^2-4=0

Substituting each x_i into the second sum gives

\displaystyle\sum_{i=1}^n\left(-\frac1{2\lambda}\right)^2=4\implies\dfrac n{4\lambda^2}=4\implies\lambda=\pm\frac{\sqrt n}4

Then we get two critical points,

x_i=-\dfrac1{2\frac{\sqrt n}4}=-\dfrac2{\sqrt n}

or

x_i=-\dfrac1{2\left(-\frac{\sqrt n}4\right)}=\dfrac2{\sqrt n}

At these points we get a value of f(x_1,\cdots,x_n)=\pm2\sqrt n, i.e. a maximum value of 2\sqrt n and a minimum value of -2\sqrt n.

6 0
4 years ago
Select the correct comparison set a set b O A the typical value is greater is set a the spread is greater in set b
salantis [7]

Answer:

(a)

Step-by-step explanation:

Given

See attachment for sets A and B

Required

The true statement about both sets

First, we calculate the typical values (mean) of set A and set B.

This is calculated as:

Mean = \frac{\sum fx}{\sum f}

For A:

A= \frac{0*1+2*1+5*1+6*1+7*1}{1+1+1+1+1}

A= \frac{20}{5}

A =4

For B:

B = \frac{7 * 1 + 8 *1 + 9 * 2 + 10 * 1}{1+1+2+1}

B = \frac{43}{5}

B = 8.6

<em>Here, we can conclude that B has a larger typical value</em>

Next calculate the spread (range) of sets A and B

This is calculated as:

Range = Highest -Least

For A:

A = 7 - 0

A = 7

For B

B=10 - 7

B = 3

<em>Here, we can conclude that A has a larger spread.</em>

<em></em>

<em>Hence, (a) is true</em>

6 0
3 years ago
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