constant of proportionality => COP
3: P(triangle ABC) = 84
COP = 18/15 = 1.2
Since you are finding the larger triangle, multiply the other numbers by 1.2
25 * 1.2 = 30
28 * 1.2 = 33.6
17 * 1.2 = 20.4
add them all up (answer up top)
5: P(triangle ABC) = 61.2
COP = 9/5 = 1.8
Since you are finding the larger triangle, multiply the other numbers by 1.8
9 * 1.8 = 16.2
13 * 1.8 = 23.4
12 * 1.8 = 21.6
add them all up (answer up top)
6: P(triangle RST) = 110
RP and PT are congruent, this means that PT is also 20
COP = 40/20 = 2
Since you are finding the larger triangle, multiply the other numbers by 2
25 * 2 = 50
20 * 2 = 40
10 * 2 = 20
add them all up (answer up top)
Two digits after the decimal point it the hundredths place
so we want to round to the place 4 is in
The number after 4 is 2, so we will round down
We will get 0.24
Answer:
C
Step-by-step explanation:
You know that if its < or >, the line is - - - -, not a fully dark line.
So it would be either A or C
Plot in some numbers for x
Less than would be to the left.
So it wouldn't be A, leaving us with C
<span>For a parallelogram to be proven to be a rectange, the opposide sides must be parallel and the two adjacent sides must be perpendicular.
For two parallel sides, the slope of the two sides is equal.
Thus, for the parallelogram to be a rectangle, AB is parallel to CD.
The slope of AB = (y2 - y1)/(x2 - x1) while the slope of CD = (y4 - y3)/(x4 - x3)
Also, BC is perpedicular to CD.
For two perpendicular sides, the product of the slopes is -1.
The slope of BC is given by (y3 - y2)/(x3 - x2).
Therefore, for the parallelogram to be a rectangle.
(y2 - y1)/(x2 - x1) = (y4 - y3)/(x4 - x3) and (y4 - y3)/(x4 - x3) x (y3 - y2)/(x3 - x2) = -1.
The third option is the correct answer.</span>
Answer:
Yes, the triangles are congruent by ASA
Step-by-step explanation:
we know that
If any two angles and the included side are the same in both triangles, then the triangles are congruent by Angle-Side-Angle (ASA)
In this problem
LK=MJ
∠KLJ=∠KMJ
∠LKJ=∠MJK
so
Two angles and the included side is equal in triangle JKL and triangle KJM
therefore
JKL≅KJM ----> by ASA
