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Reika [66]
3 years ago
13

Find a polynomial for the sum of the shaded areas of the figure. A = 6, B = 4

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
5 0

Answer:

The polynomial for the sum of the shaded  \pi r² - 20 \pi

Step-by-step explanation:

Given as :

The figure is shown which is of concentric circle with radius B , A , r

The radius B = 4 unit

The radius A = 6 unit

Let The sum of shaded portion = x unit

Now, The circumference of circle = 2 \pi R , where R is the radius

So, for circle with radius B.

The circumference = 2 \pi R = 2 \pi B

Or, The circumference = 2 \pi × 4 = 8 \pi

<u>Similarly</u>

For circle with radius A.

The circumference = 2 \piR = 2 \pi A

Or, The circumference = 2 \pi × 6 = 12 \pi

Now, <u>The area of circle with radius r is</u>

Area = \pi ×radius × radius

Or, Area = \pi r²

Now,

The sum of shaded region area = The area of circle with radius r - ( The circumference with radius B + The circumference with radius A )

Or, The sum of shaded region area =  \pi r² - ( 8 \pi + 12 \pi )

Or,  The sum of shaded region area =  \pi r² - 20 \pi

Hence The polynomial for the sum of the shaded area is \pi r² - 20 \pi  Answer

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Step-by-step explanation:

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3 years ago
Lunch at school consists of a sandwich, a vegetable, and a fruit. Each lunch combination is equally likely to be given to a stud
daser333 [38]

Answer:

a) see attachment

b) Pr(chicken sandwich, carrots, and a banana) = 1/12

c) The probability that Sol gets at least one of his favorite = 5/6

Step-by-step explanation:

a) A tree diagram is used to represent sample space.

We are told the lunch choices are sandwich, a vegetable and a fruit and each lunch combination are possible.

Find attached the tree diagram.

From the tree diagram, there are a total of 12 possible outcomes.

b) Sol's favorite lunch is a chicken sandwich, carrots, and a banana.

The probability that Sol gets his favorite lunch = Pr(chicken sandwich, carrots and a banana)

Pr(chicken sandwich, carrots, and a banana) = 1/12

Reason: From the tree diagram, the likelihood of having all three (chicken sandwich, carrots and a banana) occurs only once.

Pr(chicken sandwich, carrots and a banana) = [number of times(chicken sandwich, carrots and a banana) occurs]/(total number of possible outcomes)

Pr(chicken sandwich, carrots, and a banana) = 1/12

c) For Sol to get at least one of his favorite, we would have at least either chicken, carrot or banana in the possible outcome.

We have 10 of such possible outcome:

Chicken, carrot and apple

Chicken, carrot and banana

Chicken, spinach and apple

Chicken, spinach and banana

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Turkey, carrot and apple

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Turkey, spinach and banana

The probability that Sol gets at least one of his favorite = (total number of at least one of Sol's favorite lunch)/(total possible outcome)

= 10/12 = 5/6

The probability that Sol gets at least one of his favorite = 5/6

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3 years ago
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Step-by-step explanation:

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