Answer:
a) C. No, a carton can have a puncture and a smashed corner.
b) The probability that a carton has a puncture or a smashed corner is P(X ∪ Y) = 0.104.
Step-by-step explanation:
To be mutually exclusive, the probability of the two events happening at the same time should be 0. But the probability that a carton has a puncture and has a smashed corner is 0.004 and not 0.
Then, we can conclude the events "selecting a carton with a puncture" and "selecting a carton with a smashed corner" are not mutually exclusive.
The answer is "C. No, a carton can have a puncture and a smashed corner."
We can calculate the probability that the carton has a puncture <em>or </em>has a smashed comer simply by adding the probability of each event:
![P(X\cup Y)=P(X)+P(Y)=0.1+0.04=0.104](https://tex.z-dn.net/?f=P%28X%5Ccup%20Y%29%3DP%28X%29%2BP%28Y%29%3D0.1%2B0.04%3D0.104)
P(X ∪ Y): probability that a carton has a puncture or a smashed corner.
Answer:
D) Multiplication should be performed before addition
Answer:
8
Step-by-step explanation:
Answer:
f(n) = -34
Step-by-step explanation:
n = 20
f(n) = -2(20) + 6
f(n)= -40 +6
f(n) = -34
Answer:
x = -6
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
2(3x + 4) - 3(x - 1) = x - 1
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Distributive Property] Distribute: 6x + 8 - 3x + 3 = x - 1
- Combine like terms: 3x + 11 = x - 1
- [Subtraction Property of Equality] Subtract <em>x</em> on both sides: 2x + 11 = -1
- [Subtraction Property of Equality] Subtract 11 on both sides: 2x = -12
- [Division Property of Equality] Divide 2 on both sides: x = -6