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Gnom [1K]
3 years ago
13

Solve (5 x/3) (5 x/5) =54

Mathematics
1 answer:
Phoenix [80]3 years ago
7 0

Answer:

-\frac{9\sqrt{10} }{5}, \frac{9\sqrt{10} }{5}

Step-by-step explanation:

(5*\frac{x}{3}) * (5*\frac{x}{5} )  = 54\\ calculate the product

\frac{5x}{3} * x =54 multiply

\frac{5x^{2} }{3} = 54 multiply both sides by \frac{3}{5}

x^{2}  =\frac{162}{5}  separate into two solutions

x = ± \frac{9\sqrt{10} }{5}

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Anyone know how to do this
Anton [14]

let

(hypotenuse ) c = 10 in

(perpendicular) a = 8 in

(base) b =?

By using Pythagoras theorem

c^2= a^2+b^2

(10)^2 = (8)^2 +(b)^2

100 = 64 +(b)^2

100- 64 = (b)^2

36 = (b)^2

√36 = b

6 = b

hence b= 6 in

3 0
3 years ago
Quadratic equations of the form _____ can be solved using square roots
icang [17]

Answer:

Step-by-step explanation:

Quadratic equations of the form (x - h)^2 + k = 0 can be solved using square roots:  Take the square root of both sides, prefacing the right side with " ± "

6 0
3 years ago
Tucker walked at a rate of 1/4 a mile every 8 minutes. What was his walking rate in miles per hour.
iVinArrow [24]
He was walking 20 miles per hour
4 0
3 years ago
A student on a piano stool rotates freely with an angular speed of 2.85 rev/s . The student holds a 1.50 kg mass in each outstre
Vlad1618 [11]

Answer:r'=0.327 m

Step-by-step explanation:

Given

N=2.85 rev/s

angular velocity \omega =2\pi N=17.90 rad/s

mass of objects m=1.5 kg

distance of objects from stool r_1=0.789 m

Combined moment of inertia of stool and student =5.53 kg.m^2

Now student pull off his hands so as to increase its speed to 3.60 rev/s

\omega _2=2\pi N_2

\omega _2=2\pi 3.6=22.62 rad/s

Initial moment of inertia of two masses I_0=2mr_^2

I_0=2\times 1.5\times (0.789)^2=1.867

After Pulling off hands so that r' is the distance of masses from stool

I_0'=2\times 1.5\times (r')^2

Conserving angular momentum

I_1\omega =I_2\omega _2

(5.53+1.867)\cdot 17.90=(5.53+I_o')\cdot 22.62

I_0'=1.397\times 0.791

I_0'=5.851

5.53+2\times 1.5\times (r')^2=5.851

2\times 1.5\times (r')^2=0.321

r'^2=0.107009

r'=0.327 m

7 0
3 years ago
The Daily News offers a 15% discount on a Saturday ad that also runs on Tuesday. Skyler Sporting Company contracts for half-page
mart [117]
The ad cost for half page Saturday after discount is

15% of 380 = 0.15×380 = 57
380 - 57 = 323

The ad cost for half page Tuesday after discount is

15% of 330 = 0.15×330 = 49.5
330 - 49.5 = 280.5

Cost of the ads for 10 Saturdays and 10 Tuesdays

(10×323)+(10×280.5) = 3230+2805 = 6035
6 0
3 years ago
Read 2 more answers
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