let
(hypotenuse ) c = 10 in
(perpendicular) a = 8 in
(base) b =?
By using Pythagoras theorem
c^2= a^2+b^2
(10)^2 = (8)^2 +(b)^2
100 = 64 +(b)^2
100- 64 = (b)^2
36 = (b)^2
√36 = b
6 = b
hence b= 6 in
Answer:
Step-by-step explanation:
Quadratic equations of the form (x - h)^2 + k = 0 can be solved using square roots: Take the square root of both sides, prefacing the right side with " ± "
Answer:r'=0.327 m
Step-by-step explanation:
Given

angular velocity 
mass of objects 
distance of objects from stool 
Combined moment of inertia of stool and student 
Now student pull off his hands so as to increase its speed to 3.60 rev/s


Initial moment of inertia of two masses 

After Pulling off hands so that r' is the distance of masses from stool

Conserving angular momentum








The ad cost for half page Saturday after discount is
15% of 380 = 0.15×380 = 57
380 - 57 = 323
The ad cost for half page Tuesday after discount is
15% of 330 = 0.15×330 = 49.5
330 - 49.5 = 280.5
Cost of the ads for 10 Saturdays and 10 Tuesdays
(10×323)+(10×280.5) = 3230+2805 = 6035