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pentagon [3]
3 years ago
10

Helpppppppppppppppppppp

Mathematics
1 answer:
Ivan3 years ago
7 0
I believe the answer is B and E
You might be interested in
2 questions
Alekssandra [29.7K]

Answer:

1. A. $33 loss

2. B

Step-by-step explanation:

1. -26 - 11 - 9 +13 = -33

2. B is the only graph in which the Whole Numbers do not contain a negative or decimal (which are not WNs)

8 0
3 years ago
It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
hoa [83]

Answer:

Obese people

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, "almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ)".

Solution to the problem

Obese people

Let X the random variable that represent the minutes of a population (obese people), and for this case we know the distribution for X is given by:

X \sim N(373,67)  

Where \mu=373 and \sigma=67

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Let X the random variable that represent the minutes of a population (lean people), and for this case we know the distribution for X is given by:

X \sim N(526,107)  

Where \mu=526 and \sigma=107

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

The interval for the lean people is significantly higher than the interval for the obese people.

5 0
3 years ago
What is 38475 x 304944 ? My teacher won't let me use a calculator!
bearhunter [10]

Answer:

1,059,680,400

Step-by-step explanation:

7 0
2 years ago
Help me plzz im almost. out of time
masha68 [24]
No I do not agree with (2,-4) I believe the solution is (-4,2)
8 0
3 years ago
Jessica's penny bank is 1/3 full. After she adds 80 pennies, it is 1/2 full. How many pennies can Jessica's bank hold?
Ilia_Sergeevich [38]
3x = B
(x + 80 = 1/2B) * -3
-3x-240 = -3/2B

-240 = -1/2B
B=480 pennies



6 0
3 years ago
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