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2 years ago

Helpppppppppppppppppppp

Mathematics

1 answer:

Ivan2 years ago

7 0

I believe the answer is B and E

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Tom practiced piano 1 and 1/3 hours on Monday. If he spent half as much time practicing on Tuesday, how long did he practice on

PtichkaEL [24]

Answer: 2/3 hours

Step-by-step explanation: 1 1/3 will equal 4/3 as you have a whole number equaling 3/1 so then you divide by two and get 2/3

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2 years ago

Number 10 please I don't understand it

wel

Whats the value what ever it is its divided by three

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3 years ago

4x+5y=13 8x+7y=11 find solution of system of equation

Pavel [41]

Point Form:

(−3, 5)

Equation Form:

x = −3,y = 5

3 0

2 years ago

Carbon-14 is a radioactive isotope that has a half-life of 5,730 years. Approximately how many years will it take for carbon-14

PilotLPTM [1.2K]

Answer:

Carbon-14 will take 19,035 years to decay to 10 percent.

Step-by-step explanation:

Exponential Decay Function

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay.

An exponential decay can be described by the following formula:

$N(t)=N_{0}e^{-\lambda t}$

Where:

No = The quantity of the substance that will decay.

N(t) = The quantity that still remains and has not yet decayed after a time t

$\lambda$ = The decay constant.

One important parameter related to radioactive decay is the half-life:

$\displaystyle t_{1/2}=\frac {\ln(2)}{\lambda }$

If we know the value of the half-life, we can calculate the decay constant:

$\displaystyle \lambda=\frac {\ln(2)}{ t_{1/2}}$

Carbon-14 has a half-life of 5,730 years, thus:

$\displaystyle \lambda=\frac {\ln(2)}{ 5,730}$

$\lambda=0.00012097$

The equation of the remaining quantity of Carbon-14 is:

$N(t)=N_{0}e^{-0.00012097\cdot t}$

We need to calculate the time required for the original amout to reach 10%, thus N(t)=0.10No

$0.10N_o=N_{0}e^{-0.00012097\cdot t}$

Simplifying:

$0.10=e^{-0.00012097\cdot t}$

Taking logarithms:

$ln 0.10=-0.00012097\cdot t$

Solving for t:

$\displaystyle t=\frac{log 0.10}{-0.00012097}$

$t\approx 19,035\ years$

Carbon-14 will take 19,035 years to decay to 10 percent.

6 0

2 years ago

Read 2 more answers

A school requires students wear uniforms. They can choose from the following options. How many total choices does a student have

Svet_ta [14]

Answer:

The answer is 16

Step-by-step explanation:

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2 years ago