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4 years ago

12

Can someone please help me !!

1 answer:

jok3333 [9.3K]4 years ago

7 0

The alternate interior angle with angle 3 is angle 6

Hope this helps :)

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aticengleSidesourcesActivitiesClassify the following triangle. Check all that apply.11.9132eA. equilateralB. obtusen C. rightD.

Anuta_ua [19.1K]

The triangle is obtuse and scalene.

7 0

3 years ago

Can you guys figure this out please<br> x6∙x∙x3= x6+3 = x9

Marat540 [252]

Answer:

Below.

Step-by-step explanation:

x^6 . x . x^3

= x^6 . x^1 . x^3

= x^(6+1+3)

= x^10.

5 0

3 years ago

Question 2 (5 points)<br> What is the value of x?<br> HELP ASAP

Anton [14]

Step-by-step explanation:

$In \: \triangle HDT, \: BM || DT.. (given) \\ \\ \therefore \: \frac{HM}{MT} = \frac{ HB}{ BD} \\ (by \: basic \: proportionality \: theorem) \\ \therefore \: \frac{6}{x} = \frac{9}{15} \\ \\ \therefore \: x= \frac{15 \times 6}{9} \\ \\ \therefore \: x= \frac{90}{9} \\ \\ \therefore \: x= 10 \\ \\$

3 0

3 years ago

Which expression is equivalent to 7 (x y)?

joja [24]

Answer:

it's option c x(7y)

Step-by-step explanation:

you don't need any order to multiply

7 0

2 years ago

A homeowner plans to enclose a 200 square foot rectangular playground in his garden, with one side along the boundary of his pro

Anestetic [448]

Answer:

Therefore the length and width of the playground are 15.5 feet and 12.9 feet respectively.

Step-by-step explanation:

Given that, a homeowner plans to enclose a 200 square foot rectangle playground.

Let the width of the playground be y and the length of the playground be x which is the side along the boundary.

The perimeter of the playground is = 2(length +width)

=2(x+y) foot

The material costs $1 per foot.

Therefore total cost to give boundary of the play ground

=$[ 2(x+y)×1]

=$[2(x+y)]

But the neighbor will play one third of the side x foot.

So the neighbor will play $=\$(\frac13x)$

Now homeowner's total cost for the material is

$=\$[ 2(x+y)-\frac13x]$

$=\$[2x+2y-\frac13x]$

$=\$[2y+x+x-\frac13x]$

$=\$[2y+x+\frac{3x-x}{3}]$

$=\$[2y+x+\frac{2}{3}x]$

$=\$[2y+\frac53x]$

$\therefore C(x)=2y+\frac53x$

where C(x) is total cost of material in $.

Given that the area of the playground is 200.

We know that,

The area of a rectangle is =length×width

=xy square foot

∴xy=200

$\Rightarrow y=\frac{200}{x}$

Putting the value of y in C(x)

$\therefore C(x)=2(\frac{200}{x})+\frac53x$

The domain of C is $(0,\infty )$ .

$\therefore C(x)=2(\frac{200}{x})+\frac53x$

Differentiating with respect to x

$C'(x)= - \frac{400}{x^2}+\frac53$

Again differentiating with respect to x

$C''(x) = \frac{800}{x^3}$

To find the critical point set C'(x)=0

$\therefore 0= - \frac{400}{x^2}+\frac53$

$\Rightarrow \frac{400}{x^2}=\frac{5}{3}$

$\Rightarrow x^2 =\frac{400\times 3}{5}$

$\Rightarrow x=\sqrt{240}$

$\Rightarrow x=15.49 \approx15.5$

Therefore

$\left C''(x) \right|_{x=15.5}=\frac{800}{15.5^3}>0$

Therefore at x= 15.5 , C(x) is minimum.

Putting the value of x in $y=\frac{200}{x}$ we get

$\therefore y=\frac{200}{15.5}$

=12.9

Therefore the length and width of the playground are 15.5 feet and 12.9 feet respectively.

6 0

3 years ago