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weqwewe [10]
2 years ago
10

The goat population on a farm is decreasing at a rate of 7.25% each year. If there were 75 goats originally, how many goats will

be on the farm in 4 years?
Mathematics
1 answer:
Natasha2012 [34]2 years ago
3 0

Answer:

53

Step-by-step explanation:

x/75=7.25/100

Cross Multiply

100x = 543.75

Simplify

x=5.4375

Multiply By The Number Of Years

5.4375 x 4 = 21.75

Subtract From The Original Number

75-21.75 = 53.25

<h2>Round it down (You cant have a quarter o a sheep. It would be dead)</h2><h2>53</h2>
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39. State the equation for the line described below.
devlian [24]

Answer:

Step-by-step explanation:

39). y = -\frac{7}{8} x + 3

40). m = \frac{y_{2} -y_{1} }{x_{2} -x_{1} }

y - y_{1} = m( x - x_{1} )

(- 7, 5)

( - 12, 4)

m = ( 4 - 5 ) / ( - 12 + 7) = 1/5

y - 5 = (1/5)(x + 7) ⇒ y = \frac{1}{5} x + 6.4

8 0
2 years ago
A kangaroo hopped 1/3 of the distance to the lake with her baby in her pouch. She hopped the remaining 7040 yards without her ba
Norma-Jean [14]

Step-by-step explanation:

she hopped 10560 MI to the lake because the remaining miles was the 7040 miles without her baby and if you do 7040 (the 2/3s) divided by 2 you would get 3520 which is the 1/3 of the distance to the lake so 7040 miles + 3520 miles equals 10560 miles hopped to the lake. Hope this helped ^_^

3 0
3 years ago
Read 2 more answers
The standard form of 0.0000035
azamat
In scientific notation, the answer is 3.5*10^-6 .

I hope that this helps
5 0
2 years ago
A basic cellular phone plan costs $4 per month for 70 calling minutes. Additional time costs $0.10 per minute. The formula C= 4+
Harrizon [31]

Answer:

For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.

Step-by-step explanation:

The problem states that the monthly cost of a celular plan is modeled by the following function:

C(x) = 4 + 0.10(x-70)

In which C(x) is the monthly cost and x is the number of calling minutes.

How many calling minutes are needed for a monthly cost of at least $7?

This can be solved by the following inequality:

C(x) \geq 7

4 + 0.10(x - 70) \geq 7

4 + 0.10x - 7 \geq 7

0.10x \geq 10

x \geq \frac{10}{0.1}

x \geq 100

For a monthly cost of at least $7, you need to have at least 100 calling minutes.

How many calling minutes are needed for a monthly cost of at most 8:

C(x) \leq 8

4 + 0.10(x - 70) \leq 8

4 + 0.10x - 7 \leq 8

0.10x \leq 11

x \leq \frac{11}{0.1}

x \leq 110

For a monthly cost of at most $8, you need to have at most 110 calling minutes.

For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.

8 0
3 years ago
PLEASE HELP I GIVE THANKS
pav-90 [236]
It is (C) because the line is ZERO meaning the line is vertical and since it goes through 5, it is y=5 cuz u always have the formula for slope; y=mx+b and since there is o x intercept you just stick with the y intercept which is 5 so long story short, it is y=5 (c)
5 0
3 years ago
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