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Misha Larkins [42]
4 years ago
7

Help : Math ...........................

Mathematics
1 answer:
katen-ka-za [31]4 years ago
3 0
\frac{-6*10^{-1} }{-3*10^{-2}}

You divide -6 and -3

\frac{2*10^{-1}}{10^{-2}}

Because the exponents are both negative, you make them positive and change the position (the exponent which is at the denominator is now at the numerator and viceversa)

\frac{2*10^{2}}{10^{1}}


\frac{2*10^{2}}{10^1}

You divide the exponents (so 2-1)

2*10 = 20
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A tunnel is built in form of a parabola. The width at the base of tunnel is 7 m. On
uysha [10]

Given:

The width at the base of parabolic tunnel is 7 m.

The ceiling 3 m from each end of the base there are light fixtures.

The height to light fixtures is 4 m.

To find:

Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

Solution:

The width at the base of tunnel is 7 m.

Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.

The function of height is:

h(x)=ax(x-7)             ...(i)

Where, a is a constant.

The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

4=a(3)((3)-7)

4=a(3)(-4)

\dfrac{4}{(3)(-4)}=a

-\dfrac{1}{3}=a

Putting a=-\dfrac{1}{3}, we get

h(x)=-\dfrac{1}{3}x(x-7)              ...(ii)

The center of the parabola is the midpoint of 0 and 7, i.e., 3.

The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)

h(1.5)=-(0.5)(-5.5)

h(1.5)=2.75

Since h(1.5)<2.8, therefore the trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is not possible.

6 0
3 years ago
How can you solve a rational equation without graphing?
KiRa [710]

Answer:

To figure out the common denominator for these fractions, I'll first need to factor that quadratic in the denominator on the right-hand side of the rational equation. This will also allow me to find the disallowed values for this equation. Factoring gives me:

x2 – 6x + 8 = (x – 4)(x – 2)

The factors of the quadratic on the right-hand side "just so happen" to be duplicates of the other denominators. This often happens in these exercises. (So often, in fact, that if you get completely different factors, you should probably go back and check your work.)

Step-by-step explanation:

4 0
3 years ago
A card is drawn at random from a well-shuffled pack of 52 cards. Find the probability that the card drawn is neither a red card
Reil [10]
Number of red cards including 2 red queens = 26
Number of black queens = 2
Therefore, number of red cards including 2 red queens and 2 black queens = 26 + 2 = 28
Number of cards neither a red card nor a queen = 52 - 28 = 24

P  =  \frac{ Number \: of \: favourable \: outcomes}{ Total \: numer \: of \: possible \: outcomes}

P (neither \: a \: red \: nor \: a \: queen \: card \: ) =  \frac{24}{52}  =  \frac{6}{13}
8 0
4 years ago
Solve for x. Round to the nearest tenth if necessary.
timofeeve [1]

Answer: 41.1

Step-by-step explanation:

To find the value of x, we need to use SOH-CAH-TOA. SOH-CAH-TOA is since, cosine, and tangent. The O, A, H stands for opposite, adjacent, and hypotenuse respectively.

Looking at the figure, we see 47°. The labelled angles are adjacent and the hypotenuse. Therefore, we use CAH or cosine.

cos(47)=\frac{28}{x}             [multiply both sides by x]

xcos(47)=28           [divide both sides by cos(47)]

x=\frac{28}{cos(47)}

When we plug that into a calculator, we get x=41.1.

5 0
3 years ago
Read 2 more answers
choose a number between 67 and 113 that is a multiple of 4, 8, and 16 . Write all the numbers that she could choose. If there is
Allushta [10]
2 is a multiple of 4, so anything that's a multiple of 4 will automatically be a multiple of 2 so 3 x 4 = 12 so multiples of 12 that are between 67 and 113 are...? 12 x 6 = 72 12 x 7 = 84 12 x 8 = 96 12 x 9 = 108 <span> 72 or 84 or96 or 108 all are divisible by 2,3 and 4 all fall between 67 and 112</span>
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