Frequency = 1/time period = 1/0.05 = 20s^-1.
Differentiate the expression, to obtain expression for velocity. Set velocity to 0, this when max height is reached. Obtain the tmax from that expression.
<span>h(t) = –16t² + 32t + 6
</span><span>h'(t) = –32t² + 32
0 = </span>–32t² + 32
t max= 1
hmax = <span> –16(1)² + 32(1) + 6
hmax = 22
Therefore, first option is the correct answer.</span>
Answer:
h the books
Explanation:
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