Answer:
Electron will travel to a distance of 0.189 m before its velocity is 0
Explanation:
We have initial speed of the electron
Electric field
Charge on electron will be
Mass of electron
We know that Columbus force is equal to F = qE and according to newtons law force is equal to F = ma , here m is mass and a is acceleration
These two forces will be equal
So ma = qE
According to third equation of motion
So
s = 0.189 m
So electron will travel to a distance of 0.189 m before its velocity is 0
Well, we usually assume that the resistance of a circuit component
is constant and doesn't change. But the truth is that for anything
that conducts current, its resistance always increases somewhat
when it warms up.
For things like light bulbs, electric toasters, space heaters, electric
stove burners, the heat coils in a blow-dryer ... anything that's
designed to be really hot when it's doing its job ... the resistance
of those things increases significantly when they come up to their
operating temperatures.
Answer:tension, density, temperature and elasticity
Explanation:
We can work out the gain in GPE of the box. I'm going to take g to be 9.81 however if your qualification takes g to be 10 you'll need to change it in all the workings:
GPE = mgh
= 400 x 9.81 x 10
=39240J
So, the machine has given 39240J of energy to the box.
Therefore the minimum power generated by the motor is:
39240/8=4905W = 4.9 x 10^3 W
Note this is the <em>minimum</em> possible power generated by it and it is almost certain (well completely certain in the real world) that it will generate far more power than that because it will not be 100% efficient.
Answer:
The shortest distance in which you can stop the automobile by locking the brakes is 53.64 m
Explanation:
Given;
coefficient of kinetic friction, μ = 0.84
speed of the automobile, u = 29.0 m/s
To determine the the shortest distance in which you can stop an automobile by locking the brakes, we apply the following equation;
v² = u² + 2ax
where;
v is the final velocity
u is the initial velocity
a is the acceleration
x is the shortest distance
First we determine a;
From Newton's second law of motion
∑F = ma
F is the kinetic friction that opposes the motion of the car
-Fk = ma
but, -Fk = -μN
-μN = ma
-μmg = ma
-μg = a
- 0.8 x 9.8 = a
-7.84 m/s² = a
Now, substitute in the value of a in the equation above
v² = u² + 2ax
when the automobile stops, the final velocity, v = 0
0 = 29² + 2(-7.84)x
0 = 841 - 15.68x
15.68x = 841
x = 841 / 15.68
x = 53.64 m
Thus, the shortest distance in which you can stop the automobile by locking the brakes is 53.64 m