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matrenka [14]
3 years ago
8

A ball is thrown into the air with an upward velocity of 32 feet per second. Its height, h, in feet after t

Physics
2 answers:
LekaFEV [45]3 years ago
8 0
Differentiate the expression, to obtain expression for velocity. Set velocity to 0, this when max height is reached. Obtain the tmax from that expression.

<span>h(t) = –16t² + 32t + 6
</span><span>h'(t) = –32t² + 32
0 = </span>–32t² + 32
t max= 1

hmax = <span> –16(1)² + 32(1) + 6
hmax = 22

Therefore, first option is the correct answer.</span>
Evgesh-ka [11]3 years ago
3 0
Hello there.

<span>A ball is thrown into the air with an upward velocity of 32 feet per second. Its height, h, in feet after t
seconds is given by the function h(t) = –16t² + 32t + 6. What is the ball’s maximum height? How long does it
take the ball to reach its maximum height? Round to the nearest hundredth, if necessary. 

</span><span>Reaches a maximum height of 22 feet after 1.00 second.</span>
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A particle travels in a circle of radius 76 cm and completes one revolution in 4.5 s. What is the centripetal acceleration of th
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Answer:

<h2>2.35 N</h2>

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