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3 years ago

Which value is not part of the five-number summary needed for a box plot of this data?

2 answers:

7 0

<span>In this sequence 1,2, 5,6,7,9,12,15,18,19,27 . The median is 9 . The 1st quartile is 5 while the 3rd quartile is 18. Maximum number is 27 and the minimum number is 1. Therefore the answer is D which is 11. </span>

erma4kov [3.2K]3 years ago

5 0

Order the row {5, 6, 1, 27, 2, 7, 12, 15, 9, 18, 19} from the smallest number to the biggest number:

{1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27}.

The minimum is 1, the maximum is - 27.

The median is the middle number in this row - 9.

The median of left part {1, 2, 5, 6, 7} is 5 and the median of the right part {12, 15, 18, 19, 27} is 18.

From the option A-D only number 11 is absent (numbers 1, 5 and 9 are part of the five-number summary).

Answer: correct choice is D.

You might be interested in

Does anyone know this? its for a test , please ?!

konstantin123 [22]

Answer:

11) Irrational number

12) Integer

13) Communitive property of addition

14) Distributive property of addition and multipacation

15) 26

16) 8

17) -41

18) 65

19) -5x-20

Step-by-step explanation:

Hope I helped

4 0

3 years ago

What is the area of the composite figure?

german

Answer:

16 + 6pi cm

Step-by-step explanation:

We have a square of length 4 cm

A = s^2 = 4^2 = 16

We have 3 semi circles

with radius 2

A semi circle has an area of

1/2 pi r^2 = 1/2 pi (2)^2 = 1/2 (4pi) = 2pi

There are 3 of them

3 * 2 pi = 6pi

Add the areas together for the square and the semicircles

16 + 6pi

6 0

3 years ago

A sum of money was to be divided among A,B, and C in the ratio 2:3:5. The largest share amount to $4500 what is the total amount

Alika [10]

Answer:

2:3:5 = 480:720:1200

(a) 480+720+1200

(b) 480

Step-by-step explanation:

8 0

2 years ago

If f(x) = 2x^3 - 14x^2 + 38x -26 and x-1 is a factor of f(x) find all of the zeros of f(x) algebraically.

Anestetic [448]

Answer:

Step-by-step explanation:

First confirm that x = 1 is one of the zeros.

f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26

f(1) = 2 - 14 + 38 - 26

f(1) = -12 + 38 = + 26

f(1) = 26 - 26

f(1) = 0

=========================

next perform a long division

x -1 || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26

2x^3 - 2x^2

===========

-12x^2 + 28x

-12x^2 +12x

==========

26x -26

26x - 26

========

Now you can factor 2x^2 - 12x + 26

2(x^2 - 6x + 13)

The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16

So you are going to get a complex result.

x = -(-6) +/- sqrt(-16)

=============

x = 3 +/- 2i

f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)

The zeros are

3 +/- 2i

8 0

3 years ago

A teacher has 3 hours to grade all the papers submitted by the 35 students in her class. She gets through the first 5 papers in

Andreyy89

So, she has 3hrs to grade all papers, for 35 students.. alrite.

the first 5, she does them in 30minutes.. what's the speed rate? well, 5/30 or 1/6

now, she has still 2 hours and a half, or 150 minutes, to do the remaining 30 papers... she has to work at a rate of 30/150 then... which is 1/5 simplified.

now if we take 1/6 as the 100%, what is 1/5 in percentage then?

$\bf \begin{array}{ccllll}
rate&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
\frac{1}{6}&100\\\\
\frac{1}{5}&x
\end{array}\implies \cfrac{\frac{1}{6}}{\frac{1}{5}}=\cfrac{100}{x}\implies \cfrac{1}{6}\cdot \cfrac{5}{1}=\cfrac{100}{x}\implies \cfrac{5}{6}=\cfrac{100}{x}
\\\\\\
x=\cfrac{6\cdot 100}{5}\implies x=120$

so 1/5 is 120% in relation to 1/6... meaning the rate of 1/5 she needs to move through, namely 1 paper every 5 minutes, is 20% faster than 1/6.

8 0

3 years ago

Read 2 more answers