Answer:
f(x) = x² - 2x - 15
Step-by-step explanation:
∵ The function intersect x-axis at -3 and 5
∴ f(x) = 0 at x = -3 , 5
∵ The form of the quadratic equation is ⇒ ax² + -b/a x + c/a = 0
ax² - b/a x + c/a = 0
Where the sum of its roots is b/a and their multiplication is c/a
∵ a = 1
∵ -3 , 5 are the roots of the quadratic equation
∴ b = -3 + 5 = 2
∴ c = -3 × 5 = -15
∴ f(x) = x² - 2x - 15
Answer:
See below
Step-by-step explanation:
We start by dividing the interval [0,4] into n sub-intervals of length 4/n
![[0,\displaystyle\frac{4}{n}],[\displaystyle\frac{4}{n},\displaystyle\frac{2*4}{n}],[\displaystyle\frac{2*4}{n},\displaystyle\frac{3*4}{n}],...,[\displaystyle\frac{(n-1)*4}{n},4]](https://tex.z-dn.net/?f=%5B0%2C%5Cdisplaystyle%5Cfrac%7B4%7D%7Bn%7D%5D%2C%5B%5Cdisplaystyle%5Cfrac%7B4%7D%7Bn%7D%2C%5Cdisplaystyle%5Cfrac%7B2%2A4%7D%7Bn%7D%5D%2C%5B%5Cdisplaystyle%5Cfrac%7B2%2A4%7D%7Bn%7D%2C%5Cdisplaystyle%5Cfrac%7B3%2A4%7D%7Bn%7D%5D%2C...%2C%5B%5Cdisplaystyle%5Cfrac%7B%28n-1%29%2A4%7D%7Bn%7D%2C4%5D)
Since f is increasing in the interval [0,4], the upper sum is obtained by evaluating f at the right end of each sub-interval multiplied by 4/n.
Geometrically, these are the areas of the rectangles whose height is f evaluated at the right end of the interval and base 4/n (see picture)

but

so the upper sum equals

When
both
and
tend to zero and the upper sum tends to

Answer:
a
Step-by-step explanation:
In mathematics, the logarithm is the inverse function to exponentiation. That means the logarithm of a given number x is the exponent to which another fixed number, the base b, must be raised, to produce that number x.
Solution
<span>1) Expand
</span><span>2a+3a−12
</span>
2) Simplify 2a+3a−12
<span>5a−12
Answer = </span>5a−<span>12</span>