Ask question

Ask question

All categories

3 years ago

13

The tree diagram shows the possible win/loss paths for a basketball team playing in a tournament. Harris High School loses 1 gam

e in the tournament. How many ways could this happen?

2 answers:

nordsb [41]3 years ago

6 0

This could happen in 3 ways.

kkurt [141]3 years ago

3 0

Answer:

Option: C is the correct answer.

The number of ways of doing so is:

3

Step-by-step explanation:

L denotes the loss and W denotes the win.

Now, It is given that:

Harris High School loses 1 game in the tournament.

This means that the number of ways of doing so is: Three(3)

Out of all the 9 outcomes in the tournament , the outcomes that denotes this situation i.e. 1 loss is:

{ LWW , WLW , LWW}

Hence, total number of such outcomes=3

You might be interested in

Help I need to tune in all my late work ...

Elena-2011 [213]

Should be a scale factor of y= 1/9

8 0

3 years ago

Read 2 more answers

What is the length of BD?

Tasya [4]

The answer would be B

3 0

2 years ago

Read 2 more answers

On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th

Elena L [17]

Answer:

The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, a = $\sqrt{(3-0)^{2}+(4-0)^{2}}$

Or, a = $\sqrt{9+16}$

Or, a = $\sqrt{25}$

∴ a = 5 unit

Similarly

The measure of length BC = b = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, b = $\sqrt{(3-3)^{2}+(2-4)^{2}}$

Or, a = $\sqrt{0+4}$

Or, b = $\sqrt{4}$

∴ b = 2 unit

And

So, The measure of length CA = c = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, c = $\sqrt{(3-0)^{2}+(2-0)^{2}}$

Or, c = $\sqrt{9+4}$

Or, c = $\sqrt{13}$

∴ c = $\sqrt{13}$ unit

Now, area of Triangle written as , from Heron's formula

A = $\sqrt{s\times (s-a)\times (s-b)\times (s-c)}$

and s = $\frac{a+b+c}{2}$

I.e s = $\frac{5+2+\sqrt{13}}{2}$

Or. s = $\frac{7+\sqrt{13}}{2}$

So, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}$

Or, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}$

Or, A = $\frac{3}{2}$ × $\sqrt{1+\sqrt{13} }$

∴ Area of triangle = 1.5 $\sqrt{4.6}$

Hence The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$ Answer

7 0

3 years ago

Read 2 more answers

The length of a rectangular floor is 2m longer than it's width w. the area of the floor is 120m^2

KengaRu [80]

the width is 60

hopes this helps you

6 0

3 years ago

Mary wants to hang a mirror in her room. The mirror and frame must have an area of 7 square feet. The mirror is 2 feet wide and

Umnica [9.8K]

Answer:

The quadratic equation used to determine the thickness of frame is $\left(3+2x\right)\times \left(2+2x\right)=7$

Step-by-step explanation:

Refer to the attachment for the diagram.

Consider EFGH as the the frame and ABCD as the mirror which is to be hanged.

Let me the "x" be the thickness of the frame as shown in diagram.

Given that, BC = 3 ft and DC = 2 ft which is the dimensions of the mirror.

Now to calculate the length and width of the frame consider following calculation,

Width of frame HG = x + DC + x

Width of frame HG = x + 2 + x

Width of frame HG = 2 + 2x

2x is the addition of the thickness which is present on both side of mirror

Length of frame FG = x + BC + x

Length of frame FG = x + 3 + x

Length of frame FG = 3 + 2x

Since it is an rectangular frame, so using the formula for area of rectangle

$Area\:of\:rectangle = length \times width$

Given that area of frame is $7\:ft^{2}$

Substituting the value,

$7 = \left(3+2x\right)\times \left(2+2x\right)$

Therefore, the quadratic equation used to determine the thickness of frame is $\left(3+2x\right)\times \left(2+2x\right)=7$

8 0

3 years ago