Answer:
Part A: 15 and 100 are the coefficients!
Part B: Two terms in the expression!
Step-by-step explanation:
The values of the given numbers when it is rounded up to the nearest 10 thousands are:
<h3>What is rounding up in mathematics?</h3>
Rounding up can be described as the process that is been used in the mathematics which is been used in the estimation of a particular number in a context.
It should be noted that in rounding the a number up, it is required to look at the next digit at the right hand of the given figures in a case whereby the digit is less than 5,the digit can be rounded down, but in the case whereby the digit is more that 5 then it can be rounded up .
From the given values, we are given the 990,201 and 159,994 and if this were to rounded up to the nearest 10 thousand then we will start from the right hand sides and round down the values less than 5 and round up the values that is more that 5. and their values will be 990000
and 150000.
Read more about rounding up at:
brainly.com/question/28324571
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Well you would do 6% times 2000 (.06 *2000) 120
Answer:
The answer is 5q + 9.
Step-by-step explanation:
1) Collect like terms.
2) Simplify.
<u>hence</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>5q</u><u> </u><u>+</u><u> </u><u>9</u><u>.</u>
Answer:
Yes
Step-by-step explanation:
Permutation :
nPr = n! ÷ (n - r)!
nCr = n! ÷ (n-r)!r!
11 objects taken 3 at a time :
11P3 = 11! ÷ (11 - 3)!
11P3 = 11! / 8!
11P3 = (11 * 10 * 9 )
11P3 = 990
Dividing by 3!
3! = 3*2*1 = 6
= 990 / 6
= 165
For combination :
11C3 = 11! ÷ 8!3!
11C3 = (11 * 10 * 9) / (3 * 2 * 1)
11C3 = 990 / 6
11C3
