Question

Solve. 3x2 + 6x = 8?

Answer 1

Answer:

$x=-1+\dfrac{\sqrt{33}}{3} , x=-1-\dfrac{\sqrt{33}}{3}$

Step-by-step explanation:

To solve the equation:

$3x^{2} +6x=8$

means we have to find the value of 'x' after solving this quadratic equation

this equation could also be written as:

$3x^{2}+6x-8=0$

Also we know that for any quadratic equation of the type:

$ax^{2}+bx+c=0$

The solution is given by:

$x=\dfrac{-b+\sqrt{b^2-4ac}} {2a} ,x=\dfrac{-b-\sqrt{b^2-4ac}} {2a}$

so on comparing our given equation to the general form we have:

a=3,b=6 and c= -8

so, the value of x is:

$x=\dfrac{-6+\sqrt{36+32\times3} }{2\times 3} , x=\dfrac{-6-\sqrt{36+32\times3} }{2\times 3}$

i.e.

$x=\dfrac{-6+2\sqrt{33} }{6} ,x= \dfrac{-6-2\sqrt{33} }{6}$

which could also be written as:

$x=-1+\dfrac{\sqrt{33}}{3} , x=-1-\dfrac{\sqrt{33}}{3}$

Hence the above two values of x is the desired result.

Answer 2

If I'm reading this properly. That's 3x squared. The answer would be -1 + (sqrt33)/3 and -1 - (sqrt 33)/3.