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3 years ago

Simplify 16^-4 by making the exponent positive

1 answer:

8 0

Whenever we have a negative exponent, that means that the function should be in the denomenator. then the exponent will be positive.

Example

16^-4 = 1/(16^4)

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Find the inner product for (3,1,4)*(2,8,2) and state whether the vectors are perpendicular.

faltersainse [42]

Good evening ,

Answer:

<h2>•• Inner product = 3×2 + 1×8 + 4×2 = 22</h2><h2 /><h2>•• since 22 ≠ 0 then the vectors are not perpendicular.</h2>

5 0

3 years ago

Read 2 more answers

U guys are mean and never answer my questions, like i paid for no one to answer my question

Sav [38]

Answer:

Step-by-step explanation:

You have no grounds for making a statement like that. There are a variety of reasons why you might not get immediate answers. Be patient.

I will do the second part of this question (finding the first three numbers):

a(4) = a(3)*(-3) + 2 = -148, so a(3)*(-3) = -150 and a(3) = -50

a(3) = 50

a(2) = a(3)*(-3) + 2 = 50, so -3*a(3) = 48 and a(d) = -16

a(1) = a(2)*(-3) + 2 = -16, so a(2)*(-3) = -18 and a(1) = 6

The procedure for finding a(5), a(6) and a(7) is exactly the same.

3 0

3 years ago

The value of sports team decreases at a steady rate of 20% each year. What is the total percentage loss (to the nearest integer)

Shtirlitz [24]

It would be 80% since it decreases 20% each year so 20*4 is 80 so it’s 80%

3 0

3 years ago

G with the definition of covariance, prove cov[(ay − b),(cy − d)] = accov(x, y ), where x, y are random variables and a, b, c, d

____ [38]

By definition of covariance,

$\mathrm{Cov}(X,Y)=\mathbb E[(X-\mathbb E[X])(Y-\mathbb E[Y])]$

$\mathrm{Cov}(X,Y)=\mathbb E[XY-\mathbb E[X]Y-X\mathbb E[Y]+\mathbb E[X]\mathbb E[Y]]=\mathbb E[XY]-\mathbb E[X]\mathbb E[Y]$

We have

$\mathbb E[(aX-b)(cY-d)]=\mathbb E[acXY-adX-bcY+bd]$

$=ac\mathbb E[XY]-ad\mathbb E[X]-bc\mathbb E[Y]+bd$

$\mathbb E[aX-b]=a\mathbb E[X]-b$

$\mathbb E[cY-d]=c\mathbb E[Y]-d$

$\mathbb E[aX-b]\mathbb E[cY-d]=ac\mathbb E[X]\mathbb E[Y]-ad\mathbb E[X]-bc\mathbb E[Y]+bd$

Putting everything together, we find the covariance reduces to

$\mathrm{Cov}(aX-b,cY-d)=ac(\mathbb E[XY]-\mathbb E[X]\mathbb E[Y])=ac\mathrm{Cov}(X,Y)$

as desired.

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3 years ago

The ratio of red balloons to blue balloons is 4 to 11. There are 133 more blue balloons than red balloons. How many blue balloon

Kay [80]

The ratios of blue balloons to red balloons is 137 red balloons to 144 blue balloons

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3 years ago