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Levart [38]
3 years ago
5

How many rational numbers lie between-2/3 and 7/3​

Mathematics
2 answers:
Lemur [1.5K]3 years ago
6 0

Answer:

{x:x=-2/3-7/3}

Step-by-step explanation:

B/c ther are many rational number between them.

so that let me make some example

x>4/5 x€Q then the solution set is {x€Q:x>4/5} just like that

tiny-mole [99]3 years ago
3 0

Answer:

infinite

Step-by-step explanation:

name two, and then find a third in between them.

you can repeat that as often as you want.

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Help please I’m trying to do my homework and don’t understand
11Alexandr11 [23.1K]

Answer:

Answer is 9.

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6 0
3 years ago
Which number will have the same result when rounded to the nearest ten or hundred A-97 B-118and5 C-179 D-5091
slamgirl [31]
Lets round it to the nearest ten
A 97 ====> 100
B 118 ===> 120
C 179 ===> 180
D 5091 ==> 5090
No result yet, lets round to the nearest hindred.
A 97 ====> 100
B 118 ===> 100
C 179 ===> 180
D 5091 ==> 5100
As we can see only A give the same result when we round it to the nearest hundred and nearest ten.

5 0
3 years ago
Pauline is building a fence around her vegetable garden, what length of fence will she need to build?
Nuetrik [128]
I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
 SEE ATTACHED IMAGE. 
 First we look for the hypotenuse of both triangles.
 Left triangle:
 Sine (68.1) = (1.75) / (h)
 h = (1.75) / Sine (68.1)
 h = 1.886108667
 h = 1.9m
 Right triangle:
 Sine (49.4) = (1.75) / (h)
 h = (1.75) / Sine (49.4)
 h = 2.304841475
 h = 2.3m
 Finally adding the perimeter:
 P = 5 + 1.9 + 2.75 + 2.3
 P = 11.95 m
 Answer: 
 she will need to build 11.95 m of fence

6 0
3 years ago
Derivative of tan(2x+3) using first principle
kodGreya [7K]
f(x)=\tan(2x+3)

The derivative is given by the limit

f'(x)=\displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h

You have

\displaystyle\lim_{h\to0}\frac{\tan(2(x+h)+3)-\tan(2x+3)}h
\displaystyle\lim_{h\to0}\frac{\tan((2x+3)+2h)-\tan(2x+3)}h

Use the angle sum identity for tangent. I don't remember it off the top of my head, but I do remember the ones for (co)sine.

\tan(a+b)=\dfrac{\sin(a+b)}{\cos(a+b)}=\dfrac{\sin a\cos b+\cos a\sin b}{\cos a\cos b-\sin a\sin b}=\dfrac{\tan a+\tan b}{1-\tan a\tan b}

By this identity, you have

\tan((2x+3)+2h)=\dfrac{\tan(2x+3)+\tan2h}{1-\tan(2x+3)\tan2h}

So in the limit you get

\displaystyle\lim_{h\to0}\frac{\dfrac{\tan(2x+3)+\tan2h}{1-\tan(2x+3)\tan2h}-\tan(2x+3)}h
\displaystyle\lim_{h\to0}\frac{\tan(2x+3)+\tan2h-\tan(2x+3)(1-\tan(2x+3)\tan2h)}{h(1-\tan(2x+3)\tan2h)}
\displaystyle\lim_{h\to0}\frac{\tan2h+\tan^2(2x+3)\tan2h}{h(1-\tan(2x+3)\tan2h)}
\displaystyle\lim_{h\to0}\frac{\tan2h}h\times\lim_{h\to0}\frac{1+\tan^2(2x+3)}{1-\tan(2x+3)\tan2h}
\displaystyle\frac12\lim_{h\to0}\frac1{\cos2h}\times\lim_{h\to0}\frac{\sin2h}{2h}\times\lim_{h\to0}\frac{\sec^2(2x+3)}{1-\tan(2x+3)\tan2h}

The first two limits are both 1, and the single term in the last limit approaches 0 as h\to0, so you're left with

f'(x)=\dfrac12\sec^2(2x+3)

which agrees with the result you get from applying the chain rule.
7 0
3 years ago
Describe the association between a person's height and their name.
sesenic [268]
There isn't one. Just because you have one name doesn't mean it determines how tall you'll be.
8 0
3 years ago
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