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Liula [17]
3 years ago
13

Find the axis of symmetry for this parabola y=-2x^2+4x-10

Mathematics
1 answer:
AlekseyPX3 years ago
3 0
The answer is x equals 1
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I need some help <br> I will give you brainliest and heart!
tankabanditka [31]

Answer:

Correct!

Step-by-step explanation:

First, I'll try to solve it myself.

2(2a-1)+3a=7a-2

7a-2

4a-2=7a-2

His is very correct!

8 0
3 years ago
Write 1.052 as a percent
valina [46]
The decimal 1.052 as a percent is 105.2%.

6 0
3 years ago
Read 2 more answers
If a certain cannon is fired from a height of 8.8 meters above the​ ground, at a certain​ angle, the height of the cannonball ab
Dennis_Churaev [7]

Answer:

It would take approximately 6.50 second for the cannonball to strike the ground.

Step-by-step explanation:

Consider the provided function.

h(t)=-4.9t^2+30.5t+8.8

We need to find the time takes for the cannonball to strike the ground.

Substitute h(t) = 0 in above function.

-4.9t^2+30.5t+8.8=0

Multiply both sides by 10.

-49t^2+305t+88=0

For a quadratic equation of the form ax^2+bx+c=0 the solutions are: x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Substitute a = -49, b = 305 and c=88

t=\frac{-305+\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}=-\frac{-305+\sqrt{110273}}{98}\\t = \frac{-305-\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}= \frac{305+\sqrt{110273}}{98}

Ignore the negative value of t as time can't be a negative number.

Thus,

t=\frac{305+\sqrt{110273}}{98}\approx6.50

Hence, it would take approximately 6.50 second for the cannonball to strike the ground.

6 0
3 years ago
For each set of side listed determine if the given triangle is right triangle, obtuse or acute
nasty-shy [4]
Right triangle. You can tell because of the tiny square in the corner. This indicated that angle is equal to 90°. Any triangle that has 90° is a right triangle
3 0
3 years ago
In ΔEFG, g = 6.1 cm, f = 7.3 cm and ∠F=69°. Find all possible values of ∠G, to the nearest 10th of a degree.
yKpoI14uk [10]

Answer:

51.3

Step-by-step explanation:

4 0
3 years ago
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