Given=
length of the segment AD is 28 cm
distance between the midpoints of segments AB and CD is 16 cm
find out length of BC
To proof
AD = 28 cm
let the midpoint of the AB is E.
let the midpoint of the CD is F.
E & F are the midpoints i.e these points divide AB & CD in two equal parts.
Let BC = z
Let AE = EB = x ( E is midpoint)
Let CF = FD = y (F is midpoint)
the equation becomes
2x + 2y + z = 28
x + y + z = 16
mulitipy above equation by 2
we get
2x + 2y + 2z = 32
thus solving the equations
2x + 2y + 2z = 32
2x + 2y + z = 28
we get
z = 4 cm
i.e BC = 4 cm
Hence proved
Answer:
dc/a-b-d
Step-by-step explanation:
ax – bx = d
x + c
Multiply both sides by x + c
ax – bx
(x + c) = d(x + c)
x + c
Simplify
ax – bx
(x+c): ax – bx
x + c
ax – bx = d(x+c)
Expand d(x+c): dx + cd
ax — bx = dx + cd
Subtract dx from both sides
ax – bx – dx = dx + cd – dx
Simplify
ax – bx – dx = cd
Factor ax – bx – dx: x(a – b – d)
x(a - b- d) = cd
Divide both sides by a – b – d; a + b + d
x(a – b - d) cd
a + b + d
a - b - d
a – b-d
Simplify
X =dc/a-b-d
Answer:
M=6 OR slope=6
Step-by-step explanation:
Use slope formula
This is gcf greatest common factor
Answer:
132 degrees
Step-by-step explanation:
the angles of measure 2 and 3 have to add up to 180 degrees (because that's the angle of a straight line, which 2 and 3 make together)
180-48=132
