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Andru [333]
3 years ago
7

How do i do this? teacher didn’t help me much and i don’t understand this.

Mathematics
1 answer:
Mandarinka [93]3 years ago
4 0
Answer:

1. 17.3 millions phones were sold

2. 2011

3. I don’t have answer for it yet
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Which Question Has roots of x= -2 and x
vazorg [7]

See explanation below.

Explanation:

The 'difference between roots and factors of an equation' is not a straightforward question. Let's define both to establish the link between the two..

Assume we have some function of a single variable

x

;

we'll call this

f

(

x

)

Then we can form an equation:

f

(

x

)

=

0

Then the "roots" of this equation are all the values of

x

that satisfy that equation. Remember that these values may be real and/or imaginary.

Now, up to this point we have not assumed anything about

f

x

)

. To consider factors, we now need to assume that

f

(

x

)

=

g

(

x

)

⋅

h

(

x

)

.

That is that

f

(

x

)

factorises into some functions

g

(

x

)

×

h

(

x

)

If we recall our equation:

f

(

x

)

=

0

Then we can now say that either

g

(

x

)

=

0

or

h

(

x

)

=

0

.. and thus show the link between the roots and factors of an equation.

[NB: A simple example of these general principles would be where

f

(

x

)

is a quadratic function that factorises into two linear factors.

4 0
3 years ago
Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)
viktelen [127]
\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}

The first line segment can be parameterized by \mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle with 0\le t\le1. Denote this first segment by C_1. Then

\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt
=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt
=108

The second line segment (C_2) can be described by \mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle, again with 0\le t\le1. Then

\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt
=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt
=-\dfrac{229}3

Finally,

\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3
5 0
3 years ago
1/2y^2(6x+2y+12x-2y) is equivalent
vazorg [7]
The answer is 9y^2x(the 2 goes on top were the arrow is ) Hope this was helpful!
3 0
3 years ago
PLEASE HELP ME !!!!!!!!!!!!!!!!
natima [27]
So in slope intercept form or y=mx+b or in your case c=mx+b where b=15, x=number of movies and b=2 dollars per cd then C=2x+15 so the C intercept is when x=0 so set x to 0 and get 2(0)+15=C 0+15=C C=15 Cintercept=15 slope=m so slope=2 C intercetp=15 so if borrow certain number of movies just plug in the values for x so 1 2(1)+15=2+15=17 2 2(2)+15=4+15=19 and so on
8 0
3 years ago
What is the multiplicative inverse of c/d? Explain how a number is related to its multiplicative inverse.
Lana71 [14]

Answer:

\frac{d}{c}

Step-by-step explanation:

The multiplicative inverse of a number n is \frac{1}{n}

The product of the number and its multiplicative inverse = 1

n × \frac{1}{n} = 1

Thus the multiplicative inverse of \frac{c}{d} is

\frac{1}{\frac{c}{d} } = \frac{d}{c}

6 0
3 years ago
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