I need help with this please. i have a test on that. find the unknown length
2 answers:
Ok, from your picture, it looks like you have a square and a right triangle next to each other
one of the definition of a square is that all 4 sides are equal, and its given to you that the square has a side length of 3
since the triangle shares a side with the square, that means that shared side has a length of 3
ok, now how about determining the unknown length x
well the base has a length of 5, but you also know that when you add the length of the square side plus x, you should get 5
3+x = 5
and you can solve for x (subtract 3 from both sides)
x=2
now how about determining side length y
well since you know this is a right triangle, you can apply pythagorean theorem
where C is the hypothenuse of the triangle, or the longest side
when you substitute the known values (3 and x)
you get
3^2 + x^2 = y^2
since you already know x=2
3^2 +2^2 = y^2
and you can solve for y
any questions?
one of the definition of a square is that all 4 sides are equal, and its given to you that the square has a side length of 3
since the triangle shares a side with the square, that means that shared side has a length of 3
ok, now how about determining the unknown length x
well the base has a length of 5, but you also know that when you add the length of the square side plus x, you should get 5
3+x = 5
and you can solve for x (subtract 3 from both sides)
x=2
now how about determining side length y
well since you know this is a right triangle, you can apply pythagorean theorem
where C is the hypothenuse of the triangle, or the longest side
when you substitute the known values (3 and x)
you get
3^2 + x^2 = y^2
since you already know x=2
3^2 +2^2 = y^2
and you can solve for y
any questions?
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Step-by-step explanation:
On a single roll of a pair of dice. When a pair of dice are rolled the possible outcomes are as follows:
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
The number of outcomes that gives us 12 are (6,6). There is only one outcome that gives us sum 12.
Total outcomes = 36
Odd against favor =
Number of outcomes of getting sum 12 is 1
Number of outcomes of not getting sum 12 is 36-1= 35
odds against rolling a sum of 12=
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Step-by-step explanation:
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