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2 years ago

I need help with this please. i have a test on that. find the unknown length

Mathematics

2 answers:

lana66690 [7]2 years ago

4 0

X is 2 because 5-3=2. And Y looks like it's about 4 :)

Irina-Kira [14]2 years ago

3 0

Ok, from your picture, it looks like you have a square and a right triangle next to each other

one of the definition of a square is that all 4 sides are equal, and its given to you that the square has a side length of 3
since the triangle shares a side with the square, that means that shared side has a length of 3

ok, now how about determining the unknown length x

well the base has a length of 5, but you also know that when you add the length of the square side plus x, you should get 5

3+x = 5
and you can solve for x (subtract 3 from both sides)
x=2

now how about determining side length y
well since you know this is a right triangle, you can apply pythagorean theorem
$A^2 +B^2 = C^2$
where C is the hypothenuse of the triangle, or the longest side

when you substitute the known values (3 and x)
you get
3^2 + x^2 = y^2

since you already know x=2
3^2 +2^2 = y^2

and you can solve for y

any questions?

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A cylinder has radius r and height h. A. How many times greater is the surface area of a cylinder when both dimensions are multi

Ierofanga [76]

Answer: A. Factor 2 => 4x greater

Factor 3 => 9x greater

Factor 5 => 25x greater

Step-by-step explanation: A. A cylinder is formed by 2 circles and a rectangle in the middle. That's why surface area is given by circumference of a circle, which is the length of the rectangle times height of the rectangle, i.e.:

A = 2.π.r.h

A cylinder of radius r and height h has area:

$A_{1}$ = 2πrh

If multiply both dimensions by a factor of 2:

$A_{2}$ = 2.π.2r.2h

$A_{2}$ = 8πrh

Comparing $A_{1}$ to $A_{2}$ :

$\frac{A_{2}}{A_{1}}$ = $\frac{8.\pi.rh}{2.\pi.rh}$ = 4

Doubling radius and height creates a surface area of a cylinder 4 times greater.

By factor 3:

$A_{3} = 2.\pi.3r.3h$

$A_{3} = 18.\pi.r.h$

Comparing areas:

$\frac{A_{3}}{A_{1}}$ = $\frac{18.\pi.r.h}{2.\pi.r.h}$ = 9

Multiplying by 3, gives an area 9 times bigger.

By factor 5:

$A_{5} = 2.\pi.5r.5h$

$A_{5} = 50.\pi.r.h$

Comparing:

$\frac{A_{5}}{A_{1}}$ = $\frac{50.\pi.r.h}{2.\pi.r.h}$ = 25

The new area is 25 times greater.

B. By analysing how many times greater and the factor that the dimensions are multiplied, you can notice the increase in area is factor². For example, when multiplied by a factor of 2, the new area is 4 times greater.

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2 years ago

It costs $3.45 to buy 3/4 lb of chopped walnuts. How much would it cost to purchase 12 lbs of walnuts? Enter the numeric value o

mote1985 [20]

Answer:

$55.20

Step-by-step explanation:

Create a proportion where x is the cost of 12 lbs of walnuts:

$\frac{3.45}{0.75}$ = $\frac{x}{12}$

Cross multiply and solve for x:

0.75x = 41.4

x = 55.2

So, for 12 lbs of walnuts, it will cost $55.20

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2 years ago

todd Has a collection of 8cds and sally has a collection of 18 cds Todd is adding 9cds a month to his collection while sally is

STatiana [176]

Answer:

Step-by-step explanation:

Let's create some equations first.

Say M = number of months, T = Todd and S = Sally.

We know that Todd starts with 8 cds and sally starts with 18 cds.

This means when M= 0, T = 8 and S = 18

After one month (M = 1), Todd adds 9 cds.

This means can write the following equation:

T = 8 + 9M

So after the first month (where M = 1), we can find out that Todd has

T = 8 + 9 x 1 = 8 + 9 = 17 cds

For Sally, we know she adds 7 cds per month.

S = 18 + 7M

After one month (M = 1),

S = 18 + 7 x 1 = 25 cds.

Now we are trying to find when they will have the same number of cds and how many.

This means we are trying to figure out what M = ? when Todd and Sally are equal.

So we want to find when T = S

Remember, earlier we wrote :

T = 8 + 9M

S = 18 + 7M

If T = S, this means:

8 + 9M = 18 + 7M

Gather the like terms and solve for M.

Subtract 8 from both sides.

9M = 10 + 7M

Subtract 7M from both sides

2M = 10

Divide both sides by 2

M = 5.

So in 5 months, we are saying T = S (Todd and Sally will have the same number of cds).

Put M = 5 back into our earlier equations to find out how many cds they have after 5 months.

T = 8 + 9M

T = 8 + 9 x 5

T = 53

Therefore, after 5 months Todd and Sally will have 53 cds each :)

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2 years ago

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If the amount of monkeys is m, lions is a, and lizards is b, then a+b+m=151, 17+a=m (since there are 17 more monkeys than lions), and 30+a=b. Substituting those values in (17+a=m and 30+a=b), we have 30+17+a+a+a=151=47+3a. Subtracting 47 from both sides, we get 104=3a. Next, we can divide both sides by 3 to get 104/3=a (the number of lions), 104/3+17=the number of monkeys, and 104/3+30=the number of lizards. Somehow we end up with a fraction (not a whole number), so there are 2/3rds of monkeys floating around using this logic.

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2 years ago

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Komok [63]

Answer:

1. 5b^2-b-2 (so option 3)

2. 4x-1 (so option 2)

Step-by-step explanation:

For the first one you need to just simplify the expression

For the second one you need to combine like terms

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2 years ago

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