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2 years ago

What is it 150x8-10+25=

Mathematics

2 answers:

Likurg_2 [28]2 years ago

6 0

Answer: it should be 1,215

AysviL [449]2 years ago

5 0

Answer:

1215

Step-by-step explanation:

150 x 8 - 10 + 25 =

1200 - 10 + 25 =

1190 + 25 =

1215

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X = [?] 5x - 5 2x + 10

Ket [755]

Answer:

I thinks it’s 7x + 5

Step-by-step explanation:

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2 years ago

Plx help i need to get this so I can be ungrounded

galben [10]

Answer:

Step-by-step explanation:

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2 years ago

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Which is the graph of y = sqrt x-3

Greeley [361]

<h3>Answer: Choice B</h3>

The parent function y = sqrt(x) has the point (0,0) on it. When we subtract 3, we get y = sqrt(x)-3 which moves the point (0,0) three units down to get to (0,-3)

So (0,-3) is one point on y = sqrt(x)-3

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2 years ago

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James surveyed people at school and asked whether they bring their lunch to school or buy their lunch at school more often. The

Brrunno [24]

Answer:

The correct option is 4.

Step-by-step explanation:

Given information:

Bring lunch : 46 males, 254 females

Buy lunch : 176 males, 264 females

Total number of peoples is

$46+254+176+264=740$

Total number of males is

$46+176=222$

The probability of male is

$P(Male)=\frac{Males}{Total}=\frac{222}{740} =0.3$

Since probability of males is 0.3, therefore options A and C are incorrect.

Total number of persons who buys lunch is

$176+264=440$

The probability of persons who buys lunch is

$P(\text{Buys lunch})=\frac{\text{Buys lunch}}{Total}=\frac{440}{740} =\frac{22}{37}$

We need to find the probability of P(male | buys lunch).

According to the conditional probability, we get

$P(\frac{A}{B})=\frac{P(A\cap B)}{P(B)}$

P(male | buys lunch) $=\frac{P(\text{male }\cap \text{ buys lunch})}{P(\text{buys lunch})}$

P(male | buys lunch) $=\frac{\frac{176}{740}}{\frac{22}{37}}$

P(male | buys lunch) $=\frac{2}{5}=0.4$

Therefore the correct option is 4.

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3 years ago

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Help I cannot figure this question out.

netineya [11]

Answer:

B. x = -1 ± i

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Standard Form: ax² + bx + c = 0
Factoring
Quadratic Formula: $\displaystyle x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

Algebra II

Imaginary Numbers: √-1 = i

Step-by-step explanation:

Step 1: Define

x² + 2x = -2

Step 2: Identify Variables

Rewrite Quadratic in Standard Form [Addition Property of Equality]: x² + 2x + 2 = 0
Break up Quadratic: a = 1, b = 2, c = 2

Step 3: Solve for x

Substitute in variables [Quadratic Formula]: $\displaystyle x=\frac{-2 \pm \sqrt{2^2-4(1)(2)}}{2(1)}$
[√Radical] Evaluate exponents: $\displaystyle x=\frac{-2 \pm \sqrt{4-4(1)(2)}}{2(1)}$
Multiply: $\displaystyle x=\frac{-2 \pm \sqrt{4-8}}{2}$
[√Radical] Subtract: $\displaystyle x=\frac{-2 \pm \sqrt{-4}}{2}$
[√Radical] Factor: $\displaystyle x=\frac{-2 \pm \sqrt{-1}\sqrt{4}}{2}$
[√Radicals] Simplify: $\displaystyle x=\frac{-2 \pm 2i}{2}$
Factor: $\displaystyle x=\frac{2(-1 \pm i)}{2}$
Divide: $\displaystyle x = -1 \pm i$

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2 years ago