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Setler79 [48]
3 years ago
6

Kiran says we should add the constraint 1 is greater than or less than 0

Mathematics
1 answer:
MakcuM [25]3 years ago
3 0
Hehensjjsjsndjsnsbbsnsjsjsjsjsjsjksks
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Wayne is going to paint the side of the house shown in the diagram. What is the area that will be painted? Please explain how u
goblinko [34]
First find the area of the rectangle  by multiplying the length and width of the rectangle, so 12 x25=300. Then find the area of the triangle, which is length x height/ 2. So 8 x 25=200/2=100. Then add the two answers together to get 400.
3 0
3 years ago
Each month, a phone company charges $20 for 500 minutes of talk time plus $0.45 for each additional minute. Unlimited texting co
slavikrds [6]

Answer:

Hello there! I hope your having a good day. I'm not exactly sure about this answer: 50o=30 u+(20m+.45a)

Step-by-step explanation:

8 0
3 years ago
Mr Lowry paid $32 for 5 boxes of crayons. How many dollars per box?
butalik [34]

Answer:

6 dollars and 40 cents

Step-by-step explanation:

To get the answer, you would do 32/5 which equals 6.4, which is the same as saying 6 dollars and 40 cents.

5 0
2 years ago
What is the rate of change?<br> the second 1 and second 4?
Mumz [18]
Idek but I do know that 12x8= 72
5 0
2 years ago
Graph the image of this quadrilateral after a dilation with a scale factor of 4 centered at the origin
Brut [27]

Answer: The image is attached.

Step-by-step explanation:

A Dilation is defined as  a transformation in which the image and the pre-image have the same shape, but their sizes are different.

When the scale factor is greater than 1, the image obtained after the  dilation is greater than the pre-image and it is an "Enlargement".

When the scale factor is is between 0 and 1,  the image obtained after the  dilation is smaller than the pre-image and it is an "Reduction".

In this case we know that the scale factor is:

scale\ factor=4

Since:

4>1

It is an Enlargement.

You can identify that the vertices of the pre-image shown in the figure, are:

(-2,1)\\\\(-1,2)\\\\(0,0)\\\\(-1,-2)

So you need to multiply the coordinates of those vertices by 4 in order to get the coordinates of the image;

((-2)(4),1(4))=(-8,4)\\\\((-1)(4),(2)(4))=(-4,8)\\\\((0)(4),(0)(4)=(0,0)\\\\((-1)(4),(-2)(4))=(-4,-8)

Now you can draw it (The image is attached).

8 0
3 years ago
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