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Komok [63]
4 years ago
9

How does kinetic energy at the bottom of a hill compared to its potential energy at the top​

Chemistry
1 answer:
slavikrds [6]4 years ago
4 0

Answer:

Kinetic energy would have to work ten times harder than potential energy.

Explanation:

Let’s say you have a boulder and your asked to push it up the hill it would be difficult right? But lets reverse the situation what if you are asked to roll the boulder down the hill it wouldn’t be much work because the hill is basically doing all the work For you. Hope this Helps:)

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An oxide and carbonate containing oxygen​
exis [7]

Answer:

example of carbonate containing oxygen :

  • CaCO3

( calcium carbonate having 3 atoms of oxygen )

example of oxide containing oxygen :

  • CO2

( carbon dioxide having 2 atoms of oxygen )

5 0
3 years ago
Energy flows from the plankton to a number of other organisms when the plankton are eaten. Describe how the decrease in plankton
PIT_PIT [208]
Less plankton would mean that all the organisms that eat plankton would start to die off because they have no source of energy.
7 0
3 years ago
Please help, its urgent.
san4es73 [151]

Answer:

Mass of excess reactant left = 179.6 g

Limiting reactant = nitrogen

Mass of ammonia formed = 200.6 g

Explanation:

Given data:

Mass of nitrogen = 165.0 g

Mass of hydrogen = 215.0 g

Limiting reactant = ?

Mass of ammonia formed = ?

Mass of excess reactant left = ?

Solution:

Chemical equation:

N₂ + 3H₂    →     2NH₃

Number of moles of nitrogen:

Number of moles = mass/molar mass

Number of moles = 165.0 g/  28 g/mol

Number of moles = 5.9 mol

Number of moles of hydrogen:

Number of moles = mass/molar mass

Number of moles = 215.0 g/  2 g/mol

Number of moles = 107.5 mol

Now we will compare the moles of ammonia with both reactant.

                  H₂      :      NH₃

                   3        :       2

                  107.5  :      2/3×107.5 = 71.7 mol

                   N₂      :      NH₃

                    1        :       2

                  5.9      :      2/1×5.9 = 11.8 mol

Less number of moles of ammonia are formed by the nitrogen it will act as limiting reactant.

Mass of ammonia formed:

Mass = number of moles × molar mass

Mass = 11.8 mol × 17 g/mol

Mass = 200.6 g

Mass of hydrogen left:

We will compare the moles of hydrogen and nitrogen.

               N₂         :        H₂

                1           :          3

               5.9        :         3/1×5.9 = 17.7 mol

Out of 107.5 moles 17.7 moles of hydrogen react with nitrogen.

Number of moles left unreacted = 107.5 - 17.7 mol = 89.8 mol

Mass of hydrogen left:

Mass = number of moles × molar mass

Mass = 89.8 mol × 2 g/mol

Mass = 179.6 g

5 0
3 years ago
Write a balanced overall reaction from these unbalanced half-reactions.
ANTONII [103]
The first half reaction is:
Sn+  ->  Sn2+

You add 1 electron on the right side:
Sn+  ->  Sn2+ + 1e-

The second half reacation is:
Ag+  -> Ag

You add 1 electron to the left side:
Ag+  +  1e-  -> Ag

Then, you combine both reactions to get the balanced overall reaction since both half reactions have 1 electrons on the right and left side, respectively. You get:
Sn+  +  Ag+  ->  Sn2+  + Ag
7 0
3 years ago
Read 2 more answers
What are all the Factors affecting diffusion? (50 pts)
lyudmila [28]
There are certain factors which affects Diffusion, and they are :

1) Particle Size
2) Temperature
3) Concentration difference
4) Distance between the particles

Hope this helps!
6 0
3 years ago
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