All categories

3 years ago

Choose all the answers that apply.

Chemistry

1 answer:

PilotLPTM [1.2K]3 years ago

6 0

Answer:

Fluorine is a non-metal, fills its shell by gaining one electron and becomes a negatively charged ion.

Explanation:

Fluorine have seven electrons in its outermost shell. This means that fluorine is located in Group 17(Halogens) in the Periodic Table. Note that halogens are non-metal elements. So fluorine is a non-metal.

Fluorine fills its shell by gaining one electron because it only needs one electron to achieve stable octet electron arrangement. ( it's easier to gain one electron than to lose all seven electrons in the outermost shell)

As fluorine atom gain one electron to achieve stable octet electron arrangement, its number of electrons becomes greater than its number of protons. So it becomes a negatively charged ion.

You might be interested in

What model would represent individual atoms of different types that repeat to form a crystal

Law Incorporation [45]

Answer:

Although atoms are the smallest units that can be found in all matter, these atoms have a complex structure when experimentally analyzed. In order to understand almost all concepts in chemistry, it is essential to clearly understand the basic structure of an atom. Crystals are solid compounds made out of a number of atoms or molecules. There are particular arrangements in crystals. These arrangements are called crystal structures. Examining the crystal structure is very important in determine

Explanation:

7 0

2 years ago

Read 2 more answers

Calculate the standard free-energy change at 25 ∘C for the following reaction:

lianna [129]

Answer:

Standard free-energy change at $25^{0}\textrm{C}$ is $-3.80\times 10^{2}kJ/mol$

Explanation:

Oxidation: $Mg(s)-2e^{-}\rightarrow Mg^{2+}(aq.)$

Reduction: $Fe^{2+}(aq.)+2e^{-}\rightarrow Fe(s)$

--------------------------------------------------------------------------------------

Overall: $Mg(s)+Fe^{2+}(aq.)\rightarrow Mg^{2+}(aq.)+Fe(s)$

Standard cell potential, $E_{cell}^{0}=E_{Fe^{2+}\mid Fe}^{0}-E_{Mg^{2+}\mid Mg}^{0}$

So, $E_{cell}^{0}=(-0.41V)-(-2.38V)=1.97V$

We know, standard free energy change at $25^{0}\textrm{C}$ ( $\Delta G^{0}$ ): $\Delta G^{0}=-nFE_{cell}^{0}$

where, n is number of electron exchanged during cell reaction, 1F equal to 96500 C/mol

Here n = 2

So, $\Delta G^{0}=-(2)\times (96500C/mol)\times (1.97V)=-380210J/mol=-380.21kJ/mol=-3.80\times 10^{2}kJ/mol$

8 0

3 years ago

Read 2 more answers

Enter an abbreviated electron configuration for magnesium: Express your answer in complete form, in order of increasing energy.

stiks02 [169]

Answer:

1s2, 2s2,2p6,3s2

Explanation:

6 0

3 years ago

Read 2 more answers

How many moles are in 15 grams of Li?

svetoff [14.1K]

Answer:

there are 2.2 moles of Li in 15 grams of Li

8 0

1 year ago

Read 2 more answers

The phosphorylation of glucose to glucose 6-phosphate Group of answer choices is so strongly exergonic that it does not require

kirill115 [55]

Answer:

The phosphorylation of glucose to glucose-6-phosphate is endergonic reaction that is coupled to the exergonic hydrolysis of ATP.

Explanation:

In glycosis, the first reaction that takes place is the phosphorylation of glucose to glucose-6-phosphate by the enzyme hexokinase. This is an exergenic reaction. This is a coupled reaction in which phosphorylation of glucose is coupled to ATP hydrolysis. The free energy of ATP hydrolysis fuels glucose phosphorylation.

5 0

3 years ago