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Lina20 [59]
3 years ago
9

Solve for x: b(5px-3c)=a(qx-4)

Mathematics
1 answer:
shtirl [24]3 years ago
6 0
5pbx-3bc=aqx-4a
5pbx-aqx=3bc+4a
x=3bc+4a/5pb-aq

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Sergei buys a rectangular rug for his living room. He measures the diagonal of the rug to be 18 feet. The length of the rug is 3
kvv77 [185]
The correct answer is d. Please give me brainlest I hope this helps let me know if it’s correct or not okay
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3 years ago
Convert these unlike fractions to equivalent like fractions and add them. You must use the LCD to get the answer correct. If pos
Kamila [148]

Answer:

3

Step-by-step explanation:

The fractions are: \frac{1}{5} and \frac{2}{3}. Let's take a look at the denominators: 5 and 3. The LCD of 5 and 3 is 15. 5x3=15, 3x5=15. So now we would multiply the denominators to make them the same number like this: \frac{5}{15} and \frac{10}{15}. Remember that if you multiply the denominator by a certain number, you must multiply the numerator by the same number as well. For example, in \frac{2}{3}, we multiply 3 by 5 and 2 by 5. Same number. Now with that out of the way, let's work on the equation: \frac{1}{5} + \frac{2}{3}. We know it is the same as \frac{5}{15} and \frac{10}{15}. So now all we do is add the numerators together: 5+10=15 or \frac{15}{15}. Now we have to reduce the fraction. \frac{15}{15} can be reduced to 3 by dividing 15 by 5=3. The final fraction is \frac{3}{3} or can be simply put as 3 since 3/3 is a whole number. That's it - you're done!

7 0
2 years ago
A drinking water project construct a cubical tank of 20m long what is the capacity of the tank​
earnstyle [38]
3.45 is the answer I think

4 0
3 years ago
What is the value of thi expression when d=3?
Leni [432]

Answer:

73

Step-by-step explanation:

Givens

d = 3

Equation 7d^2 + 10 = ?

Solution

7*3*3 + 10                

7*9 + 10

63 + 10 = 73

4 0
4 years ago
Read 2 more answers
Suppose that the functions p and q are defined as follows.p(x) = -2x + 1q(x)=-x?Find the following.
MariettaO [177]

First let us find

(q\mathrm{}p)(x)\begin{gathered} q(p(x))=q(-2x+1) \\ =-(-2x+1)^2 \\ So\text{ } \\ (q\mathrm{}p)(5)=-(-2\times5+1)^2 \\ =-(9)^2 \\ =-81 \end{gathered}

Now let;s solve the second part

\begin{gathered} (p\mathrm{}q)(x)=p(q(x)) \\ =p(-x^2) \\ =-2(-x^2)+1 \\ =2x^2+1 \\ So\text{ (p.q)(5) will be } \\ (p\mathrm{}q)(5)=2(5)^2+1 \\ =51 \end{gathered}

6 0
1 year ago
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