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Lady_Fox [76]
2 years ago
9

Which one represent the solution.

Mathematics
1 answer:
bixtya [17]2 years ago
5 0

Answer:

N is less than 2, (C)

Step-by-step explanation:

Divide both sides by -6, and since two negatives make a positive, you get n is less then 2.  

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The basketball shown is packaged in a box that is in the shape of a cube. The edge length of the box is equal to the diameter of
Roman55 [17]

Answer:

since i dont know what the diameter is ill give you this formula

Step-by-step explanation:

A=6a2            2 means squared     plug the diameter in for lowercase a and solve           brainliest plz

4 0
3 years ago
6−3(5x+2)−10x please explain the steps on how to simplify this polynomials.
kati45 [8]

Step-by-step explanation:

6-15x-6-10x

put the like terms together and it's now -15x-10x+6-6

-25+6-6

=-25

6 0
1 year ago
Paige used 1 1/2 cups of flour and 1/4 cup of butter to make 12 muffins. How much flour and butter would palat
yanalaym [24]

Answer:

D

Step-by-step explanation:

To turn the fraction of 1 1/2 to decimal would be : 1.50 add fifty percent because you have to add 6 to 12 and six is half, so you add half. Half of 150 is 75 so add them you get 225 and as a fraction, that's 2 1/4. Already you have the first part done. Since there is only one answer with 2 1/3 your answer has to be D.

7 0
2 years ago
Zeno jumped 8 meters. Then he jumped half as far again (4 meters). Then he jumped half as far again (2 meters). So after 3 jumps
Gekata [30.6K]

14/2 = 7

7/2 = 3.5

3.5/2 = 1.75

1.75/2 = 0.875

4 0
3 years ago
Read 2 more answers
A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,
guajiro [1.7K]

We have been given that a huge ice glacier in the Himalayas initially covered an area of 45 square kilo-meters. The relationship between A, the area of the glacier in square kilo-meters, and t, the number of years the glacier has been melting, is modeled by the equation A=45e^{-0.05t}.

To find the time it will take for the area of the glacier to decrease to 15 square kilo-meters, we will equate A=15 and solve for t as:

15=45e^{-0.05t}

\frac{15}{45}=\frac{45e^{-0.05t}}{45}

\frac{1}{3}=e^{-0.05t}

Now we will switch sides:

e^{-0.05t}=\frac{1}{3}

Let us take natural log on both sides of equation.

\text{ln}(e^{-0.05t})=\text{ln}(\frac{1}{3})

Using natural log property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

-0.05t\cdot \text{ln}(e)=\text{ln}(\frac{1}{3})

-0.05t\cdot (1)=\text{ln}(\frac{1}{3})

-0.05t=\text{ln}(\frac{1}{3})

t=\frac{\text{ln}(\frac{1}{3})}{-0.05}

t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-0.05\cdot 100}

t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-5}

t=-\text{ln}(\frac{1}{3})\cdot 20

t=-(\text{ln}(1)-\text{ln}(3))\cdot 20

t=-(0-\text{ln}(3))\cdot 20

t=20\text{ln}(3)

Therefore, it will take 20\text{ln}(3) years for area of the glacier to decrease to 15 square kilo-meters.

6 0
3 years ago
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