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atroni [7]
3 years ago
9

What number has factors of 2 and 3 and 12 and 18 as multiples?

Mathematics
2 answers:
Firlakuza [10]3 years ago
8 0
6 is the answer
 
hope this help
lawyer [7]3 years ago
5 0
Here you go!

Factors-                    Multiples-
1,2, 3, 6    is    6      is    12
1,7            is    7      is    14
1, 2, 4, 8   is    8      is     16
1, 3, 9       is    9      is      18
<span>______________________________________________________________
</span>
You see the 12, 14, 16, and the 18? We're counting by twos. 
<span>______________________________________________________________
</span>            Hope This Helps You! Have A Great Holiday!
<span>                                                  ~GlitterWolfy~</span>
                
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Please help 10pts each
cestrela7 [59]
X=2

subtract 5x on both sides
-2x=-4
divide by -1 on both sides
2x=4
divide by 2 on both sides
x= 2
6 0
2 years ago
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How do I solve this and what kind of formula is it?
soldier1979 [14.2K]

Answer:

160

Step-by-step explanation:

The measure of an arc is always twice the degree of the corresponding angle inside the circle. For example, the measure of arc DC is just double the measure of angle DOC; angle DOC is 44 degrees, so arc DC must be 88 degrees.

Angle COB is 80 degrees, so arc CB is 160 degrees.

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3 years ago
Lao wrote the number 85 on the board is 85 prime or composite explain
ELEN [110]

85 is composite because it can be divided by 5 and 17

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3 years ago
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PLEASE HELP ME TO SOLVE THIS QUESTION WITH STEP-BY-STEP. THANK YOU!!!​
Alexeev081 [22]

Answer:

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3 years ago
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Help I don’t understand at all
zloy xaker [14]

Answer:

1)\ \ 4h^2-13h+6\\2)\ \ 7x^3y^2-x^2y+1\\3)\ \ -7n+2\\4)\ \ -8m+4

Step-by-step explanation:

1.

Simplify the expression by combining like terms. Remember, like terms have the same variable part, to simplify these terms, one performs operations between the coefficients. Please note that a variable with an exponent is not the same as a variable without the exponent. A term with no variable part is referred to as a constant, constants are like terms.

2h^2-7h+2h^2-h+6+4h-9h

(2h^2+2h^2)+(-7h-h+4h-9h)+(6)

4h^2-13h+6

2.

Use a very similar method to solve this problem as used in the first. Please note that all of the rules mentioned in the first problem also apply to this problem; for that matter, the rules mentioned in the first problem generally apply to any pre-algebra problem.

8x^3y^2-7x^2y+8x-4-x^3y^2+2x^2y+4x^2y-8x+5

(8x^3y^2-x^3y^2)+(-7x^2y+2x^2y+4x^2y)+(8x-8x)+(-4+5)

7x^3y^2-x^2y+1

3.

Use the same rules as applied in the first problem. Also, keep the distributive property in mind. In simple terms, the distributive property states the following (a(b+c)=(a)(b)+(a)(c)=ab+ac). Also note, a term raised to an exponent is equal to the term times itself the number of times the exponent indicates. In the event that the term raised to an exponent is a constant, one can simplify it. Apply these properties here,

-2(8n+1)-(5-9n)+3^2

-2(8n+1)-(5-9n)+(3*3)

-2(8n+1)-(5-9n)+9

(-2)(8n)+(-2)(1)+(-)(5)+(-)(-9n)+9

-16n-2-5+9n+9

(-16n+9n)+(-2-5+9)

-7n+2

4.

The same method used to solve problem (3) can be applied to this problem.

\frac{1}{2}(10-8m+6m^2)-(3m^2+4m-7)-2^3

\frac{1}{2}(10-8m+6m^2)-(3m^2+4m-7)-(2)(2)(2)

(\frac{1}{2})(10)+(\frac{1}{2})(-8m)+(\frac{1}{2})(6m^2})+(-)(3m^2)+(-1)(4m)+(-1)(-7)-8

5-4m+3m^2-3m^2-4m+7-8

(-3m^2-3m^2)+(-4m-4m)+(5+7-8)

-8m+4

8 0
3 years ago
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