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3 years ago

Hello, can someone pls help me ty!

Mathematics

1 answer:

max2010maxim [7]3 years ago

7 0

Answer:

C, 5/2

Step-by-step explanation:

3 I2x -1I + 4 = 16

Isolate absolute value:

3 I2x -1I + 4 - 4 = 16 - 4

3 I2x -1I= 12

(3 I2x -1I) / 3 = 12 / 3

I2x -1I= 4

Since the question is only asking for the positive, all you need to solve for is the +4. Solve for x

2x -1 = 4

2x -1 + 1 = 4 +1

2x = 5

2x / 2 = 5 / 2

x = 5/2 or C

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sashaice [31]

<span>Well first this one you can just count which ones are 9 units away so it could be A becuase -4+-9=-13
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4 0

3 years ago

Read 2 more answers

Maria weighs 55 kilograms. What is her weight in pounds?

ICE Princess25 [194]

Answer:

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Step-by-step explanation:

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2 years ago

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What is the answer to the equation (x-5)^2=40

Citrus2011 [14]

Answer:

x^2 -10x - 15 = 0

(don't know how far you want me to go)

Step-by-step explanation:

(x - 5)^2 = 40

(expand the brackets)

(x - 5)(x - 5) = 40

x^2 -5x -5x + 25 = 40

x^2 -10x + 25 = 40

x^2 -10x - 15 = 0

3 0

3 years ago

Two cyclists leave towns 253 kilometers apart at the same time and travel towards each other. One cyclist travels 5km/h faster t

Sladkaya [172]

Answer:

The rate of the slower cyclist is

$22\frac{4}{5}km/h$

and that of the faster cyclist is

$27 \frac{4}{5}km/h$

Step-by-step explanation:

We let x be the rate of the slower cyclist

$rate \times time = distance$

From the question, the distance between the two towns is 253 and the time taken for the two cyclist to meet is 5 hours

so we can write the equation

$5x + 5(x + 5) = 253$

We simplify to get the value for x

$\implies5x + 5x + 25 = 253$

$\implies10x = 253 - 25$

$\implies10x = 228$

$\implies x =22 \frac{4}{5}$

Hence the rate of the slower cyclist is

$22 \frac{4}{5} km/h$

and that of the rate faster cyclist is

$27 \frac{4}{5}km/h$

5 0

3 years ago

0.42 is 15% of what number

julia-pushkina [17]

Answer:

2.8

Step-by-step explanation:

You have to divide 0.42 by 15%.

0.42 / 15% = 2.8

6 0

2 years ago

Hello, can someone pls help me ty!​

Hello, can someone pls help me ty!