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rusak2 [61]
3 years ago
9

Hello, can someone pls help me ty!​

Mathematics
1 answer:
max2010maxim [7]3 years ago
7 0

Answer:

C, 5/2

Step-by-step explanation:

3 I2x -1I + 4 = 16

Isolate absolute value:

3 I2x -1I + 4 - 4 = 16 - 4

3 I2x -1I= 12

(3 I2x -1I) / 3 = 12 / 3

I2x -1I= 4

Since the question is only asking for the positive, all you need to solve for is the +4. Solve for x

2x -1 = 4

2x -1 + 1 = 4 +1

2x = 5

2x / 2 = 5 / 2

x = 5/2 or C

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Determine whether the given segments have the same length. Complete the justification of your answer,
Ratling [72]

Answer:

No does not contain the same length

Step-by-step explanation:

Given that

A(-4,2) , B (1,4), C (2, -1)

Now

AB would be

= \sqrt{(1-(-4))^2 + (4-2)^2} \\\\= \sqrt{29}

And, BC is

= \sqrt{(2-1)^2 + 1-(-4))^2} \\\\= \sqrt{26}

As we can see that the AB and BC are not equaled

So,

AB ≠ BC

Due to the different length

Therefore they do not contains the same length

We simply applied the distance formula due to which the length could be determined and the same is to be considered

5 0
3 years ago
What is the answer to <br> 2x=24
Digiron [165]

Answer:

12

Step-by-step explanation:

you divide 24 by 2 because it is multiplication, and the opposite is division.

5 0
3 years ago
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Use decimals to spray is 0.719 in expanded form
miss Akunina [59]
The answer would be 0.+0.7+0.01+0.009 hope it helps
6 0
3 years ago
What is the distance between begin ordered pair 8 comma negative 3 comma 4 end ordered pair and begin ordered pair 6 comma negat
katen-ka-za [31]

Answer:

d = \sqrt{14} = 3.74...

Step-by-step explanation:

To find the distance between (8, -3, 4) and (6, -4, 1), use the distance formula for (x,y,z) points. It is very similar to (x,y) points.

d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2 + (z_2 - z_1)^2} \\d = \sqrt{(8 - 6)^2 + (-3--4)^2 + (4-1)^2} \\d = \sqrt{(2)^2 + (1)^2 + (3)^2} \\d = \sqrt{4 + 1 + 9}\\ d = \sqrt{14} = 3.74...

5 0
3 years ago
Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997, However in march 1997 the price of the tea increased by 25% and
Irina18 [472]

Answer: tea = 15 rupees  per kg

sugar= 3 rupees per kg

Step-by-step explanation:

Hi, to answer this question we have to write a system of equations with the information given:

<em>"Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997": </em>

2 t + 3 s =39 (a)

Where:

  • t= price of 1 kg of tea
  • s = price of 1 kg of sugar

<em>"in march 1997 the price of the tea increased by 25% (1.25)and the price of the sugar increased by 20%(1.20) and the same quantity of tea and sugar cost rupees 48.30. "</em>

2(t1.25)+3(s1.2) = 48.30 (b)

  • <em>Solving for t in (b) </em>

2t =39-3s

t = (39 -3s)/2

t = 19.5-1.5s

  • <em>Replacing the value of t in (b) </em>

2 x ((19.5-1.5s)1.25)+ 3 ( 1.2s) =48.30

2x ( 24.375 -1.875s) +3.6s =48.30

48.75 -3.75s+3.6s= 48.30

48.75-48.30 = 3.75s-3.6s

0.45= 0.15s

0.45/0.15 =s

3 =s

  • <em>Replacing the value of s in (a) </em>

2 t + 3 (3) =39

2 t + 9 =39

2 t =39 -9

2 t =30

t = 30/2

t= 15

Prices in january:

tea = 15 rupees per kg

sugar= 3 rupees per kg

Feel free to ask for more if needed or if you did not understand something.

4 0
2 years ago
Read 2 more answers
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