Question

Two cyclists leave towns 253 kilometers apart at the same time and travel towards each other. One cyclist travels 5km/h faster than the other. If they meet in 5 hours , what is the rate of each cyclist. Please answer ASAP can anyone assist with this I am up against the clock can anyone help. I will give a 5 star and brainiest

Answer 1

Answer:

The rate of the slower cyclist is

$22\frac{4}{5}km/h$

and that of the faster cyclist is

$27 \frac{4}{5}km/h$

Step-by-step explanation:

We let x be the rate of the slower cyclist

$rate \times time = distance$

From the question, the distance between the two towns is 253 and the time taken for the two cyclist to meet is 5 hours

so we can write the equation

$5x + 5(x + 5) = 253$

We simplify to get the value for x

$\implies5x + 5x + 25 = 253$

$\implies10x = 253 - 25$

$\implies10x = 228$

$\implies x =22 \frac{4}{5}$

Hence the rate of the slower cyclist is

$22 \frac{4}{5} km/h$

and that of the rate faster cyclist is

$27 \frac{4}{5}km/h$