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pshichka [43]
3 years ago
13

Two cyclists leave towns 253 kilometers apart at the same time and travel towards each other. One cyclist travels 5km/h faster t

han the other. If they meet in 5 hours , what is the rate of each cyclist. Please answer ASAP can anyone assist with this I am up against the clock can anyone help. I will give a 5 star and brainiest
Mathematics
1 answer:
Sladkaya [172]3 years ago
5 0

Answer:

The rate of the slower cyclist is

22\frac{4}{5}km/h

and that of the faster cyclist is

27 \frac{4}{5}km/h

Step-by-step explanation:

We let x be the rate of the slower cyclist

rate \times time = distance

From the question, the distance between the two towns is 253 and the time taken for the two cyclist to meet is 5 hours

so we can write the equation

5x + 5(x + 5) = 253

We simplify to get the value for x

\implies5x + 5x  + 25 = 253

\implies10x = 253 - 25

\implies10x = 228

\implies x =22 \frac{4}{5}

Hence the rate of the slower cyclist is

22 \frac{4}{5} km/h

and that of the rate faster cyclist is

27 \frac{4}{5}km/h

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