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kvasek [131]
3 years ago
7

If AABC is reflected across the y-axis, what are the coordinates of A'?

Mathematics
1 answer:
tino4ka555 [31]3 years ago
4 0

Answer:

-2,-4

Step-by-step explanation:

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Consider the following hypothesis test.H0:μ1−μ2=0 Ha:μ1−μ2≠0The following results are for two independent samples taken from the
Julli [10]

Answer:

a) z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53  

b) p_v =2*P(z

c) Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

Step-by-step explanation:

Information given

\bar X_{1}= 104 represent the mean for 1

\bar X_{2}= 106 represent the mean for 2

\sigma_{1}= 8.4 represent the population standard deviation for 1

\sigma_{2}= 7.6 represent the population standard deviation for 2

n_{1}=80 sample size for the group 1

n_{2}=70 sample size for the group 2

z would represent the statistic

Hypothesis to test

We want to check if the two means for this case are equal or not, the system of hypothesis would be:

H0:\mu_{1}=\mu_{2}

H1:\mu_{1} \neq \mu_{2}

The statistic would be given by:

z =\frac{\bar X_1-\bar X_2}{\sqrt{\frac{\sigma^2_1^2}{n_1} +\frac{\sigma^2_2^2}{n_2}}}=(1)

Part a

Replacing we got:

z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53

Part b

The p value would be given by this probability:

p_v =2*P(z

Part c

Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

6 0
3 years ago
Johnathan ran 5 days this week. The most he ran in one day was 3.5 miles. Write an inequality that shows the distance johnathan
Mekhanik [1.2K]

<em><u>An inequality that shows the distance Johnathan could of ran any day this week is:</u></em>

x\leq 3.5

<em><u>Solution:</u></em>

Let "x" be the distance Johnathan can run any day of this week

Given that,

Johnathan ran 5 days this week. The most he ran in one day was 3.5 miles

Therefore,

Number of days ran = 5

The most he ran in 1 day = 3.5 miles

Thus, the maximum distance he ran in a week is given as:

distance = 5 \times 3.5 = 17.5

The maximum distance he ran in a week is 17.5 miles

If we let x be the distance he can run any day of this week then, we get a inequality as:

x\leq 3.5

If we let y be the total distance he can travel in a week then, we may express it as,

y\leq 17.5

8 0
3 years ago
Show work how you know it’s a function or not a function for each problem. PLEASE SOMEONE HELP ME OUT
Fudgin [204]

Answer: Function, not a function, Function, not a function

Step-by-step explanation:

For it to be a function, each value of x has to map onto one value of y.

  1. This is a function.
  2. Not a function since x=-1 has more than one y value.
  3. This is a function
  4. Not a function since x=-6 has more than one y value.
7 0
2 years ago
Question 10(Multiple Choice Worth 5 points)
Zinaida [17]
The answer is D. 2b+7
5 0
4 years ago
Which trend line has been drawn correctly using the divide-center method?
dangina [55]

Answer:

I'm pretty sure its C but some please correct me if I'm wrong.

3 0
3 years ago
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