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oee [108]
4 years ago
14

What is the answer to the equation (x-5)^2=40

Mathematics
1 answer:
Citrus2011 [14]4 years ago
3 0

Answer:

x^2 -10x - 15 = 0

(don't know how far you want me to go)

Step-by-step explanation:

(x - 5)^2 = 40

(expand the brackets)

(x - 5)(x - 5) = 40

x^2 -5x -5x + 25 = 40

x^2 -10x + 25 = 40

x^2 -10x - 15 = 0

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The domain of u(x) is the set of all real values except 0 and the domain of v(x) is the set of all real values except 2. What
Oksana_A [137]

Using the domain concept, the restrictions on the domain of (u.v)(x) are given by:

A. u(x) ≠ 0 and v(x) ≠ 2.

<h3>What is the domain of a data-set?</h3>

The domain of a data-set is the set that contains all possible input values for the data-set.

To calculate u(x) x v(x) = (u.v)(x), we calculate the values of u and v and then multiply them, hence the restrictions for each have to be considered, which means that statement A is correct.

Summarizing, u cannot be calculated at x = 0, v cannot be calculated at x = 2, hence uv cannot be calculated for either x = 0 and x = 2.

More can be learned about the domain of a data-set at brainly.com/question/24374080

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3 0
2 years ago
Find the measure of the exterior angle 1. with one angle is 50 degrees and 28 degrees​
OLga [1]

Answer:

D. 78°

Step-by-step explanation:

50°+28°= 78°

_______

3 0
3 years ago
. The mean width of 12 iPads is 5.1 inches. The mean width of 8 Kindles is 4.8 inches. a. What is the total width of the iPads?
UkoKoshka [18]

Answer:

a) 61.2, b) 38.4 and c) 4.98

Step-by-step explanation:

Given:

The mean width of 12 I-Pads is 5.1 inches.

The mean width of 8 Kindles is 4.8 inches.

Question asked:

a. What is the total width of the I-Pads?

b. What is the total width of the Kindles?

c. What is the mean width of the 12 I-Pads and 8 Kindles?

Solution:

<u>As we know:</u>

<u />Mean =\frac{Sum\ of\ observations}{Number\ of\ observations}\\ \\ Mean\ width =\frac{Sum\ of\ width\ of\ all \ I-pad}{Number \  of\ I-pad}

5.1=\frac{Sum\ of\ width\ of\ all\ I-pad}{12} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all\ I-pad}=5.1\times1 2\\ \\ Sum\ of\ width\ of\ all\ I-pad}= 61.2

a) Thus, the total width of the I-Pads are 61.2 inches.

Mean\ width =\frac{Sum\ of\ width\ of\ all\ Kindles}{Number \  of\ Kindles}

4.8=\frac{Sum\ of\ width\ of\ all\Kindles}{8} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all \ Kindles=4.8\times8\\ \\ Sum\ of\ width\ of \ all\ Kindles}=38.4

b) Thus, total width of the Kindles are 38.4 inches.

Combined width of both I-pad and Kindles = 61.2 + 38.4 = 99.6 inches

Combined number of observations = 12 + 8 =20

Combined mean of width of the 12 I-Pads and 8 Kindles = Combined width of both I-pad and Kindles \div Combined number of observations

Combined mean of width of the 12 I-Pads and 8 Kindles = \frac{99.6}{20} =4.98\ inches

c) Thus, the mean width of the 12 I-Pads and 8 Kindles is 4.98 inches.

5 0
3 years ago
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