Answer:
The empirical formula of the compound is 
.
Explanation:
Mass of magnesium in compound = 0.273 g
Mass of nitrogen in the compound = 0.105 g
Moles of magnesium =
Moles of nitrogen = 
Form empirical formula divides the lowest value of moles of an element present with all the moles of elements present.
Magnesium 
Nitrogen 
The empirical formula of a compound:
The empirical formula of the compound is .
Answer:
Butanoic acid present in solution
Explanation:
In this case, we have a buffer solution of butanoic acid and sodium butanoate. In other words a reaction like this:
HC₄H₇O₂ + H₂O <------> C₄H₇O₂⁻ + H₃O⁺ Ka = 1.5x10⁻⁵
The low value of Ka means that this is a weak acid. So, after this, the NaOH is added to the solution.
The NaOH is a really strong base, so we might expect that the pH of the solution increase drastically, however this do not occur.
The reason for this is because the first thing to happen in this reaction is an acid base reaction.
The NaOH react with the butanoic acid still present in solution, because is a weak acid, so in solution, this acid is not completely dissociated into it's respective ions. So the butanoic acid reacts with the NaOH and the products:
HC₄H₇O₂ + NaOH <------> Na⁺C₄H₇O₂⁻ + H₂O
So, because of this, the pH increase but not much.
Answer:
mass of sodium reacted is 184.1 g
Explanation:
mass Na = X = ?
∴ mass NaCl = 468 g
∴ mass Cl = 0.248 g
∴ molar mass NaCl = 58.44 g/mol
∴ atomic mass Cl = 35.453 a.m.u
∴ atomic mass Na = 22.989 a.m.u
⇒ moles Na = (X gNa)*(mol Na/22.989 g) = X/22.989 mol Na
⇒ mass NaCl = (X/22.989 mol Na)*(mol NaCl/mol Na)*(58.44 gNaCl/mol NaCl) = 468 g NaCl
clearing "X":
⇒ ((58.44)(X))/(22.989) = 468 g
⇒ X = 184.1 g = mass Na reacted
Answer:
S+ F2 ⇒ SF
S=1
F =2
So S +F2 ......... 2SF
2S + F2 ..........2SF this is a balance equation
S=2 F=2 in left side s=2 F = 2 in rightside
Explanation:⇆
⇒
Ice is simply just frozen water, so it's formula would be the same was water: H2O
