All categories

3 years ago

Using chemical equations, show how the triprotic acid H3PO4 ionizes in water. Phases, such as (l) or (aq), are optional.

1 answer:

4 0

H3PO4 --> H+ + H2PO4 1-
H2PO4 1- --> H+ + HPO4 2-
HPO4 2- --> H+ + PO4 3-

Ka1 = [H+][H2PO4 1-] / [H3PO4]
Ka2 = [H+][HPO4 2-] / [H2PO4 1-]
Ka3 = [H+][PO4 3-] / [HPO4 2-

You might be interested in

Suppose you have 300.0 mL of a 0.1000 M solution of a strong acid (HCl), and you add this to 100.0 mL of a 0.0200 M solution of

Ganezh [65]

Answer:

ph=150.0ml

Explanation:

BOy im on you boy

5 0

3 years ago

Highest energy level for lithium

Karo-lina-s [1.5K]

QUESTION :

highest energy level for lithium

ANSWER :

There are 2 electrons on the first energy level and 1 electron on the second. Explain that the first energy level can only have 2 electrons so the next electron in lithium is on the next (second) level. Explain that neon has 10 protons and 10 electrons.

3 0

3 years ago

A powder sample weighing 250 g and having a surface area of 1 m2/g is dispersed in 1 L of water. After 10 minutes, 0.4 g of the

lisabon 2012 [21]

Answer:

$K = 2.64 * 10^{-8}$

$15 \frac{5}{8}$ hours

Explanation:

Given

Surface Area (S) of 250 grams of powder sample $= 250$ square meter.

$S = 2500000$ square centimeter

$V\frac{dC}{dT} = 0.40$ grams/minute

$V\frac{dC}{dT} = \frac{dM}{dT} = \frac{0.40*60}{10} = 0.66$ mg per second

$C_s = 0.01$ gram per cubic meter $= 10$ mg/ml

$\frac{dM}{dT} = K SC_s$

$0.66 = K* 2500000* 10\\$

$K = 2.64 * 10^{-8}$ cm /sec

b) Time taken

Time taken to sink

$\frac{10*60}{0.4} * 37.5 = 56,250$

Time in hours

$15 \frac{5}{8}$ hours

6 0

3 years ago

Luba_88 [7]

Answer:

yes u are correct as it define that

7 0

3 years ago

During the phosphatase experiment you will use several different ph buffers. the ph value depends upon combing various ratios of

Elan Coil [88]

First calculate mass of sodium hydrogen phosphate (Na₂HPO₄) needed for solution:
n(Na₂HPO₄) = V(Na₂HPO₄) · c(Na₂HPO₄)
n(Na₂HPO₄) = 0,3 dm³ · 0,2 mol/dm³
n(Na₂HPO₄) = 0,06 mol
m(Na₂HPO₄) = 0,06 mol · 142 g/mol
m(Na₂HPO₄) = 8,52 g.
Measure that mass on scale using spoon and beaker. Than dissolve salt in beaker with distilled water and pour that solution in volumetric flask (size 300 mL), pour distilled water to graduation mark.

7 0

3 years ago