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3 years ago

Balance the following equation: Sg + F2 --> SF

Chemistry

1 answer:

Tanzania [10]3 years ago

3 0

Answer:

S+ F2 ⇒ SF

S=1

F =2

So S +F2 ......... 2SF

2S + F2 ..........2SF this is a balance equation

S=2 F=2 in left side s=2 F = 2 in rightside

Explanation:⇆

⇒

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Calculate the number of moles of iodine in 7.68×10^25 molecules of I2

Dmitrij [34]

Answer:

<h2>127.57 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{7.68 \times {10}^{25} }{6.02 \times {10}^{23} } \\ = 127.574750...$

We have the final answer as

<h3>127.57 moles</h3>

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2 years ago

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3 years ago

When a pot of water has been boiling vigorously for several minutes, the bubbles that emerge from the liquid water are composed

kumpel [21]

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3 years ago

A rock contains 0.623 mg of 206Pb for every 1.000 mg of 238U present. Assuming that no lead was originally present, that all the

maxonik [38]

Answer:

t = 3,496x10⁹ years

Explanation:

The decay of ²³⁸U is:

²³⁸U → ²⁰⁶Pb + 8He + 6e⁻

Moles of ²⁰⁶Pb presents in 0,623mg are:

0,623x10⁻³g×(1mol / 206g) = 3,02x10⁻⁶ moles of ²⁰⁶Pb.

These moles are equals to moles of ²³⁸U before decay, that means, 3,02x10⁻⁶ moles²³⁸U

In grams:

3,02x10⁻⁶ moles²³⁸U× (238g / 1mol) = 7,20x10⁻⁴ g ²³⁸U = 0,720 mg²³⁸U

That means initial ²³⁸U was 1,000mg + 0,720mg =<em> 1,720mg</em>

Applying the formula:

ln (N₀/N) t₁₂ = t ln2

Where N₀ is initial amount of uranium (1,720mg), N is concentration of uranium (1,000mg), half-life time is a constant (t₁₂= 4,468x10⁹ years) and t is the time transcurred for the reaction. Replacing:

ln(1,720/1)*4,468x10⁹ years = t ln2

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3 years ago

(23.4m)(14m) rounded off to the correct number of significant figures

VARVARA [1.3K]

The value of the given expression up to correct significant figures is $330 m^2$ .

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