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Karolina [17]
3 years ago
6

Balance the following equation: Sg + F2 --> SF

Chemistry
1 answer:
Tanzania [10]3 years ago
3 0

Answer:

S+ F2 ⇒ SF

S=1

F =2

So S +F2 ......... 2SF

2S + F2 ..........2SF this is a balance equation

S=2 F=2 in left side s=2 F = 2 in rightside

Explanation:⇆

⇒

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What information is needed to calculate the average atomic mass of an element?(1 point)
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Answer:

Taking into account the definition of average atomic mass and isotopes of an element, the information that you need is the masses of its isotopes and their percent abundances.

Each chemical element is characterized by the number of protons in its nucleus, which is called the atomic number Z.

But in the nucleus of each element it is also possible to find neutrons, whose number can vary. The atomic mass (A) is obtained by adding the number of protons and neutrons in a given nucleus.

The same chemical element can be made up of different atoms, that is, their atomic numbers are the same, but the number of neutrons is different. These atoms are called isotopes of the element.

The atomic mass of an element is the weighted average mass of its natural isotopes. Therefore, the atomic mass of an element is not a whole number.

The weighted average means that not all isotopes have the same percentage.

In other words, the atomic masses of chemical elements are usually calculated as the weighted average of the masses of the different isotopes of each element, taking into account the relative abundance of each of them.

Explanation:

7 0
3 years ago
Saturated fatty acids and unsaturated fatty acids differ in.
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Answer:

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4 0
2 years ago
How much CaCO3 would have to be decomposed to produce 247 g of CaO
vovangra [49]

441 g CaCO₃ would have to be decomposed to produce 247 g of CaO

<h3>Further explanation</h3>

Reaction

Decomposition of CaCO₃

CaCO₃ ⇒ CaO + CO₂

mass CaO = 247 g

mol of CaO(MW=56 g/mol) :

\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{247}{56}\\\\mol=4.41

From equation, mol ratio CaCO₃ : CaO = 1 : 1, so mol CaO :

\tt \dfrac{1}{1}\times 4.41=4.41

mass CaCO₃(MW=100 g/mol) :

\tt mass=mol\times MW\\\\mass=4.41\times 100\\\\mass=441~g

6 0
3 years ago
8x10^-200 in significant figures PLEASE IVE BEEN STUCK ON IT FOR 2 HOURS
weqwewe [10]
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3 0
3 years ago
How many grams of NaCl are required to make 150.0 mL of a 5.000 m solution
Oksi-84 [34.3K]

The  grams   of NaCl  that are required  to  make  150.0 ml of  a  5.000 M  solution is  43.875 g


calculation

Step 1:calculate  the  number of moles

moles =  molarity  x volume  in L

volume  = 150 ml / 1000 = 0.15 L

= 0.15 L  x 5.000  M  = 0.75  moles

Step 2:  calculate mass

mass =  moles x  molar mass

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mass is therefore =0.75  moles  x 58.5  mol /l =43.875 g

4 0
3 years ago
Read 2 more answers
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