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storchak [24]
3 years ago
5

A sample of sodium reacts completely with 0.284 kg of chlorine, forming 468 g of sodium chloride. What mass of sodium reacted?

Chemistry
1 answer:
Verizon [17]3 years ago
4 0

Answer:

mass of sodium reacted is 184.1 g

Explanation:

  • Na + Cl → NaCl

mass Na = X = ?

∴ mass NaCl = 468 g

∴ mass Cl = 0.248 g

∴ molar mass NaCl = 58.44 g/mol

∴ atomic mass Cl = 35.453 a.m.u

∴ atomic mass Na = 22.989 a.m.u

⇒ moles Na = (X gNa)*(mol Na/22.989 g) = X/22.989 mol Na

⇒ mass NaCl = (X/22.989 mol Na)*(mol NaCl/mol Na)*(58.44 gNaCl/mol NaCl) = 468 g NaCl

clearing "X":

⇒ ((58.44)(X))/(22.989) = 468 g

⇒ X = 184.1 g = mass Na reacted

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What are the list of catalysts that can be used for hydrogenation of nitrobenzene???​
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A sample of sodium hydroxide (NaOH) has a mass of 160. 0 g. The molar mass of NaOH is 40. 00 g/mol. How many moles of NaOH does
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<h3>How we calculate moles?</h3>

Moles of any substance will be calculated as:

n = W/M, where

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Moles of NaOH is calculated as:

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6 0
3 years ago
If 5.0 grams of sucrose, C12H22O11, are dissolved in 10.0 grams of water, what will be the boiling point of the resulting soluti
GaryK [48]

Answer : The boiling point of the resulting solution is, 100.6^oC

Explanation :

Formula used for Elevation in boiling point :

\Delta T_b=i\times k_b\times m

or,

T_b-T^o_b=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}

where,

T_b = boiling point of solution = ?

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k_b = boiling point constant  = 0.52^oC/m

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

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w_1 = mass of solvent (water) = 10.0 g

M_2 = molar mass of solute (sucrose) = 342.3 g/mol

Now put all the given values in the above formula, we get:

(T_b-100)^oC=1\times (0.52^oC/m)\times \frac{(5.0g)\times 1000}{342.3\times (10.0g)}

T_b=100.6^oC

Therefore, the boiling point of the resulting solution is, 100.6^oC

5 0
3 years ago
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