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uranmaximum [27]
3 years ago
12

Avril invested 60,000 in a partnership with Lane, Jules, Ray, Ravi, and Petra. The total investment of all partners was $320,000

. What percent of the business does avril own?
Mathematics
1 answer:
8090 [49]3 years ago
8 0

Answer:

Percentage\ of\ Avril=18.75\%

Step-by-step explanation:

Concept Used: Percentage: x\ amount\ of\ y.\ Percentage=\frac{x}{y}\times 100

Total\ investment=\$320000\\\\Avril's\ Investment=\$60000\\\\Percentage\ of\ Avril=\frac{Avril's\ investment}{Total\ investment}\times 100\\\\Percentage\ of\ Avril=\frac{60000}{320000}\times 100\\\\Percentage\ of\ Avril=\frac{60000}{3200}\\\\Percentage\ of\ Avril=18.75\%

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Write an equation of a parabola that passes through (3,-30) and has x-intercepts of -2 and 18. Then find the average rate of cha
Nookie1986 [14]

Answer:

The equation of the parabola is y = \frac{2}{5}\cdot x^{2}-\frac{32}{5}\cdot x -\frac{72}{5}.  The average rate of change of the parabola is -4.

Step-by-step explanation:

We must remember that a parabola is represented by a quadratic function, which can be formed by knowing three different points. A quadratic function is standard form is represented by:

y = a\cdot x^{2}+b\cdot x + c

Where:

x - Independent variable, dimensionless.

y - Dependent variable, dimensionless.

a, b, c - Coefficients, dimensionless.

If we know that (3, -30), (-2, 0) and (18, 0) are part of the parabola, the following linear system of equations is formed:

9\cdot a +3\cdot b + c = -30

4\cdot a -2\cdot b +c = 0

324\cdot a +18\cdot b + c = 0

This system can be solved both by algebraic means (substitution, elimination, equalization, determinant) and by numerical methods. The solution of the linear system is:

a = \frac{2}{5}, b = -\frac{32}{5}, c = -\frac{72}{5}.

The equation of the parabola is y = \frac{2}{5}\cdot x^{2}-\frac{32}{5}\cdot x -\frac{72}{5}.

Now, we calculate the average rate of change (r), dimensionless, between x = -2 and x = 8 by using the formula of secant line slope:

r = \frac{y(8)-y(-2)}{8-(-2)}

r = \frac{y(8)-y(-2)}{10}

x = -2

y = \frac{2}{5}\cdot (-2)^{2}-\frac{32}{5}\cdot (-2)-\frac{72}{5}

y(-2) = 0

x = 8

y = \frac{2}{5}\cdot (8)^{2}-\frac{32}{5}\cdot (8)-\frac{72}{5}

y(8) = -40

r = \frac{-40-0}{10}

r = -4

The average rate of change of the parabola is -4.

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3 years ago
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If the ratio of the length of segment AC to the length of segment CB is 3:1, what is the y-coordinate of point C?
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Answer:

The coordinates of point C are (8,8.5)

Step-by-step explanation:

The picture of the question in the attached figure

Let

(C_x,C_y) ----> coordinates of point C

we have that

The horizontal distance AB is equal to

AB_x=10-2=8\ units

The vertical distance AB is equal to

AB_y=10-4=6\ units

Find the horizontal coordinate of point C

we know that

\frac{AC}{CB}=\frac{3}{1}

so

\frac{AC_x}{CB_x}=\frac{3}{1}

AC_x=3CB_x----> equation A

AC_x+CB_x=8 ----> equation B

substitute equation A in equation B

3CB_x+CB_x=8

4CB_x=8\\CB_x=2

AC_x=3(2)=6

so

The x-coordinate of point C is equal to the x-coordinate of point A plus the horizontal distance between the point A and point C

C_x=A_x+AC_x=2+6=8

Find the vertical coordinate of point C

we know that

\frac{AC}{CB}=\frac{3}{1}

so

\frac{AC_y}{CB_y}=\frac{3}{1}

AC_y=3CB_y----> equation A

AC_y+CB_y=6 ----> equation B

substitute equation A in equation B

3CB_y+CB_y=6

4CB_y=6\\CB_y=1.5

AC_y=3(1.5)=4.5

so

The y-coordinate of point C is equal to the y-coordinate of point A plus the vertical distance between the point A and point C

C_y=A_y+AC_y=4+4.5=8.5

therefore

The coordinates of point C are (8,8.5)

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