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GREYUIT [131]
4 years ago
13

Match the reasons with the statements given. Given: 1 = 2 5 = 6 Prove: MQ = MP 1. ∠3, ∠5 are supplementary and ∠4, ∠6 are supple

mentary ASA 2. ∠5 = ∠6 and ∠1 = ∠2 CPCTE 3. ∠3 = ∠4 Supplements to = angles. 4. MN = MN Exterior sides in opposite rays. 5. Triangle MNQ congruent to Triangle MNP Reflexive 6. MQ = MP Given
Mathematics
2 answers:
Serjik [45]4 years ago
8 0

1.<3,<5 are supplementary and <4, <6 are supplementary -Exterior sides in opposite rays

2. <5=<6 and <1=<2 - Given

3. <3=<4 - Supplements to = angles

4. MN=MN - Reflexive

5. Triangle MNQ congruent to Triangle MNP - ASA

6. MQ=MP - CPCTE

madam [21]4 years ago
4 0
Do you have a diagram to go with this ill be able to help if you did
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Calculate the factorization 16w^2+48w+36=(4w+[1])^2
stiv31 [10]

Answer:

  [1] = 6

  x = -3/2 is the root

Step-by-step explanation:

A perfect square trinomial is of the form ...

  (a + b)² = a² +2ab +b²

You have ...

  • a²=16w²   ⇒   a = 4w
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  • 2ab = 2(4w)(6) = 48w

Then the factorization is ...

  16w² +48w +36 = (4w +6)²

This will be zero when x = -6/4 = -3/2.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Give an example of a polynomial that has the asymptotes of x=5 and y=0.5
BaLLatris [955]
(x²+4x+3)/2(x²-10x+25)

the horizontal asymptote when the numerator and the denominator have the same degree (in this case, both of a degree of 2) is ration of the coefficients of the numerator and denominator. In this case, the coefficient for numerator x² is 1, and the coefficient for the denominator 2x² is 2, so the horizontal asymptote is y=1/2=0.5

the vertical asymptote is the x value. the denominator cannot be zero, if x²-10x+25=0, x would be 5, so the vertical asymptote is x=5 

this is just one example. There can be others:
(2x²+5x+2)/[(4x-7)(x-5)]  for another example, but this example has a second vertical asymptote 4x-7=0 =>x=7/4
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Answer:

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Step-by-step explanation:

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