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Nataliya [291]
3 years ago
10

If 3m+5=23, what's 2m-3?

Mathematics
2 answers:
Andreas93 [3]3 years ago
6 0
M= 6 so 2m would be 12 and 12-3=9
Darina [25.2K]3 years ago
3 0

Answer:

9

Step-by-step explanation:

First, you solve the initial equation 3m+5=23.

3m+5-5=23-5

3m=18

3m/3=18/3

m=6

Second, you input the answer 6 into m in the second equation.

2(6)-3

12-3

=9

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Did I do the first question right? can anyone please help me with the 2nd question? Would really appreciate the Help​
IgorC [24]

Answer:

  8.  1483.33

  9.  21 months

Step-by-step explanation:

8. Morgan's income after taxes is 55000/12 = 4583.33 per month. The amount  available after expenses is 4583.33 -3100.00 = 1483.33 per month.

Morgan is able to put $1483.33 per month into savings.

__

9. If Morgan is able to save $1483.33 per month, it will take her ...

  $30,000/$1483.33 ≈ 20.2

months to save $30,000. After 20 months, she won't have quite enough, so it will take her one more month to save the desired amount.

It will take Morgan about 21 months to save $30,000.

_

If you like, you can write an equation for "m", the number of months it will take Morgan to save 30,000:

  1483.33×m = 30,000

  m = 30,000/1483.33 ≈ 20.2 . . . . . . divide by the coefficient of m

7 0
3 years ago
Can somebody help me?
Vikentia [17]
9+3t is your answer.......
8 0
3 years ago
Read 2 more answers
The Math Club is renting a banquet room for a party with door prizes. The banquet room costs
juin [17]

Answer:

14

Step-by-step explanation:

8 0
3 years ago
Brainly.com
Slav-nsk [51]
The answer is a, because the absolute value of x(the actual weight of the product) minus the target weight of 18.25 needs to be greater that the target weight difference of .36 so that it is outside the range.  So basically, any number outside of the range will be correct.You can plug in number that you know are in/ out of the acceptable range of numbers for this problem in.  
|18.62-18.25|>.36
.37>.36
18.62 is not in range.





7 0
3 years ago
Read 2 more answers
The Quadratic Equation c² + 6c+ 8 = 0<br><br> Show work please
Bad White [126]
The formula for the quadratic formula is x (c in this case) = (-b(+/-)√(b²-4ac))/2a
This is used for an equation in standard quadratic form: ax² + bx + c = 0
1.) Put it in the correct form, if not already in it.
Ex. c² + 6c + 8 = 0
2.) Identify each part of the equation:
a = 1 (the leading coefficient), b = 6 (the coefficient in front of the second variable), c = 8
3.) Plug in each variable answer
c = (-6(+/-)√(6²-4(1)(8))/2(1)
4.) Simplify
c = (-6(+/-)√(36-(4*8))/2
c = (-6(+/-)√(36-32))/2
c = (-6(+/-)√(4))/2
c = (-6(+/-)2)/2
*Here, the equation splits in two. It becomes:
c = (-6+2)/2 AND c = (-6-2)/2
*Simplify again:
c = -4/2 AND c = -8/2
c = -2 AND c = -4
The answers c = -2 and c = -4 would solve the given equation.
Hope this helps! :)
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4 years ago
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