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brilliants [131]
3 years ago
8

Haley had 56 dollars she spent 5/8 of her money on a new shirt how much money did she have left after buying the shirt

Mathematics
1 answer:
Mrac [35]3 years ago
3 0

First you would multiply $56 by 5/8:

56 * 5/8 = 35

Now you know that she spent $35 on the shirt. So, subtract 35 from 56 and that's your answer.

56 - 35 = 21

Haley has $21 after buying the shirt. :)

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29/512 divided by 21 1/3
tatuchka [14]
<span>The answer is 3.983724</span>
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3 years ago
Pleas someone help find the answer -1/5+3/5=
KonstantinChe [14]

Answer:

0.4

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3 0
3 years ago
Read 2 more answers
A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student
yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

The information provided is as follows:

n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43

The critical value of <em>z</em> for 98% confidence level is,

z_{\alpha/2}=z_{0.02/2}=2.326

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

     =(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0
3 years ago
Can someone help me find x please
a_sh-v [17]

Answer:

38.7°

Step-by-step explanation:

We can solve the triangle using the trigonometrical ratios which may be expressed in the form SOA CAH TOA Where

SOA stands for

Sin Ф = opposite side/hypotenuses side

CAH stands for

Cosine Ф = adjacent side/hypotenuses side

TOA stands for

Tangent Ф = opposite side/adjacent side

The hypotenuse is the side facing the right angle while the opposite is the side facing the given angle.

Considering the triangle with respect to angle x, 8cm is the opposite side, 10cm is the adjacent side

hence

Tan x = 8/10

Tan x = 0.8

x = tan -1 0.8

= 38.7°

4 0
3 years ago
/<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx-9%7D%7B15%7D%20%3D%5Cfrac%7B2x-9%7D%7B10%5C%5C%7D" id="TexFormula1" title="\frac{
motikmotik

Step-by-step explanation:

\frac{x - 9}{15}  =  \frac{2x - 9}{10}  \\

\frac{x - 9}{3}  =  \frac{2x - 9}{2}  \\

2( x - 9) = 3(2x - 9) \\

2x - 18 = 6x - 27

27 - 18 = 6x - 2x

9 = 4x

x =  \frac{9}{4} \\

5 0
2 years ago
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