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2 years ago

Y+3=2(x-1) im not so sure that i got the answer correct.

1 answer:

8 0

So just try it for x=1 how many will get for y

y+3=2(x-1) for x = 1 will get y+3 =2(1-1) so y+3=2*0 so y+3=0 so y=-3

x=1
y=-3 so choice A.(1,-3) is right sure

hope this will help you

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An equilateral triangle has perimeter P. The length of one side is P/3. Which expression is equivalent to the length on one side

irina1246 [14]

Answer: $3\times \dfrac{P}{3}=P$

Step-by-step explanation:

Given

The perimeter of one equilateral triangle is P

The lengths of the equilateral triangle are equal

Suppose x is the length of each side

$\therefore 3\times x=P\\\\\Rightarrow x=\dfrac{P}{3}$

i.e.

$\Rightarrow 3\times \dfrac{P}{3}=P$

3 0

3 years ago

Parallel / Perpendicular Practice

deff fn [24]

The slope and intercept form is the form of the straight line equation that includes the value of the slope of the line

Neither
║
Neither
⊥
║
Neither
Neither
Neither

Reason:

The slope and intercept form is the form y = m·x + c

Where;

m = The slope

Two equations are parallel if their slopes are equal

Two equations are perpendicular if the relationship between their slopes, m₁, and m₂ are; $m_1 = -\dfrac{1}{m_2}$

1. The given equations are in the slope and intercept form

$\ y = 3 \cdot x + 1$

The slope, m₁ = 3

$y = \dfrac{1}{3} \cdot x + 1$

The slope, m₂ = $\dfrac{1}{3}$

Therefore, the equations are neither parallel or perpendicular

Neither

2. y = 5·x - 3

10·x - 2·y = 7

The second equation can be rewritten in the slope and intercept form as follows;

$y = 5 \cdot x -\dfrac{7}{2}$

Therefore, the two equations are parallel

3. The given equations are;

-2·x - 4·y = -8

-2·x + 4·y = -8

The given equations in slope and intercept form are;

$y = 2 -\dfrac{1}{2} \cdot x$

Slope, m₁ = $-\dfrac{1}{2}$

$y = \dfrac{1}{2} \cdot x - 2$

Slope, m₂ = $\dfrac{1}{2}$

The slopes

Therefore, m₁ ≠ m₂

$m_1 \neq -\dfrac{1}{m_2}$

The lines are Neither parallel nor perpendicular

Neither

4. The given equations are;

2·y - x = 2

$y = \dfrac{1}{2} \cdot x +1$

m₁ = $\dfrac{1}{2}$

y = -2·x + 4

m₂ = -2

Therefore;

$m_1 \neq -\dfrac{1}{m_2}$

Therefore, the lines are perpendicular

5. The given equations are;

4·y = 3·x + 12

-3·x + 4·y = 2

Which gives;

First equation, $y = \dfrac{3}{4} \cdot x + 3$

Second equation, $y = \dfrac{3}{4} \cdot x + \dfrac{1}{2}$

Therefore, m₁ = m₂, the lines are parallel

6. The given equations are;

8·x - 4·y = 16

Which gives; y = 2·x - 4

5·y - 10 = 3, therefore, y = $\dfrac{13}{5}$

Therefore, the two equations are neither parallel nor perpendicular

Neither

7. The equations are;

2·x + 6·y = -3

Which gives $y = -\dfrac{1}{3} \cdot x - \dfrac{1}{2}$

12·y = 4·x + 20

Which gives

$y = \dfrac{1}{3} \cdot x + \dfrac{5}{3}$

m₁ ≠ m₂

$m_1 \neq -\dfrac{1}{m_2}$

Neither

8. 2·x - 5·y = -3

Which gives; $y = \dfrac{2}{5} \cdot x +\dfrac{3}{5}$

5·x + 27 = 6

$x = -\dfrac{21}{5}$

Therefore, the slopes are not equal, or perpendicular, the correct option is Neither

Learn more here:

brainly.com/question/16732089

6 0

3 years ago

Write the equation of the line that passes through the given points (0,2)) and (-9, -3)

Irina18 [472]

Step-by-step explanation:

Y= m x+ C

m (slope ) = 2 - (_3) / 0 _( - 9 )

= 5 / 9

( O, 2 ) Satisfying equation

2= 5/9 ( 0) + C

C= 2

So eq. is

y= 5/ 9 X + 2

7 0

3 years ago

Solutions to 39=4-7v

pishuonlain [190]

V = -5 because you subtract 4 from both sides then divide both sides by -7 and you get -5

4 0

3 years ago

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for the fair, organizers order 32 rolls of tickets. each rolls has 100 tickets. how many tickets were ordered in all?

MatroZZZ [7]

Each roll has 100 tickets, and 32 were bought.

Multiply 32 with 100

32 x 100 = 3200

3200 tickets were bought in all

hope this helps

6 0

3 years ago

Read 2 more answers